我希望传播tibble
作为矩阵,第一列为如下所示的rownames:
必需
E1 E2
G1 0.5855288 -1.8179560
G2 0.7094660 0.6300986
G3 -0.1093033 -0.2761841
G4 -0.4534972 -0.2841597
G5 0.6058875 -0.9193220
获得
到目前为止得到以下
E1 E2
[1,] 0.5855288 -1.8179560
[2,] 0.7094660 0.6300986
[3,] -0.1093033 -0.2761841
[4,] -0.4534972 -0.2841597
[5,] 0.6058875 -0.9193220
最低工作示例
使用给定的代码
set.seed(12345)
Y <- rnorm(10)
Env <- paste0("E", rep(1:2, each = 5))
Gen <- paste0("G", rep(1:5, times = 2))
df1 <- data.frame(Y, Env, Gen)
library(magrittr)
library(tidyverse)
df1 %>%
tidyr::spread(key = Env, value = Y) %>%
dplyr::ungroup() %>%
dplyr::select(-Gen) %>%
as.matrix()
答案 0 :(得分:1)
在我们使用layout(binding = 0, std140) uniform uCommon
时,该选项为magrittr
set_rownames
也可以使用library(tidyverse)
df1 %>%
spread(Env, Y) %>%
set_rownames(.$Gen) %>%
select(-Gen) %>%
as.matrix
# E1 E2
#G1 0.5855288 -1.8179560
#G2 0.7094660 0.6300986
#G3 -0.1093033 -0.2761841
#G4 -0.4534972 -0.2841597
#G5 0.6058875 -0.9193220
acast
来完成
reshape2