Question

library(tidyverse)

使用底部的样本数据，我想找到Gender和FP变量的计数，然后使用tidyr :: spread（）传播这些变量。我试图通过创建一个数据帧列表来实现这一点，一个用于性别计数，另一个用于FP计数。我这样做的原因是最终同时绑定两个数据帧。但是，我在将tidyr :: spread合并到我的函数中时遇到了麻烦。

下面的函数会创建一个包含性别和FP计数的两个数据框的列表，但计数不会“传播”。

  group_by_quo=quos(Gender,FP)

 DF2<-map(group_by_quo,~DF%>%
    group_by(Code,!!.x)%>%
    summarise(n=n()))

如果我添加tidyr :: spread，它就不起作用。我不确定如何合并，因为列表中的每个数据帧都有不同的变量。

group_by_quo=quos(Gender,FP)

 DF2<-map(group_by_quo,~DF%>%
    group_by(Code,!!.x)%>%
    summarise(n=n()))%>%
    spread(!!.x,n)

任何帮助将不胜感激！

示例代码：

Subject<-c("Subject1","Subject2","Subject1","Subject3","Subject3","Subject4","Subject2","Subject1","Subject2","Subject4","Subject3","Subject4")
Code<-c("AAA","BBB","AAA","CCC","CCC","DDD","BBB","AAA","BBB","DDD","CCC","DDD")
Code2<-c("AAA2","BBB2","AAA2","CCC2","CCC2","DDD2","BBB2","AAA2","BBB2","DDD2","CCC2","DDD2")
Gender<-c("Male","Male","Female","Male","Female","Female","Female","Male","Male","Male","Male","Male")
FP<-c("F","P","P","P","F","F","F","F","F","F","F","F")
DF<-data_frame(Subject,Code,Code2,Gender,FP)

Answer 1

我认为你放错了右括号。这段代码适合我：

library(tidyverse)

Subject<-c("Subject1","Subject2","Subject1","Subject3","Subject3","Subject4","Subject2","Subject1","Subject2","Subject4","Subject3","Subject4")
Code<-c("AAA","BBB","AAA","CCC","CCC","DDD","BBB","AAA","BBB","DDD","CCC","DDD")
Code2<-c("AAA2","BBB2","AAA2","CCC2","CCC2","DDD2","BBB2","AAA2","BBB2","DDD2","CCC2","DDD2")
Gender<-c("Male","Male","Female","Male","Female","Female","Female","Male","Male","Male","Male","Male")
FP<-c("F","P","P","P","F","F","F","F","F","F","F","F")
DF<-data_frame(Subject,Code,Code2,Gender,FP)

group_by_quo <- quos(Gender, FP)

DF2 <- map(group_by_quo,
  ~DF %>%
    group_by(Code,!!.x) %>%
    summarise(n=n()) %>%
    spread(!!.x,n))

最后一部分使用count更简洁：

DF2 <- map(group_by_quo,
  ~DF %>%
    count(Code,!!.x) %>%
    spread(!!.x,n))

通过使用count，也可以删除不必要的分组信息。

需要帮助将Tidyr的Spread整合到一个函数中，该函数输出带有分组计数的数据帧列表

1 个答案: