Question

我试图将字符串中的所有字符放入数组中自己的索引中，并尝试将" "（空格）替换为0。我得到的错误就是说

？错误的参数数量（给定0，预期为1）

但我不确定如何让include(' ')工作。

这是我的代码：

def findMe(words)
  x = 0
  convert = []

  while x < words.length
    if words[x].is_a? String && words[x].include? != " "
      convert << words[x]
    else
      convert << 0
    end
    x = x + 1
  end

  p convert

end

findMe('Words and stuff.')

所需输出：["W", "o", "r", "d", "s", 0, "a", "n", "d", 0, "s", "t", "u", "f", "f", "."]

Answer 1

你得到的错误数量的参数＆＃34;错误在这里：

class DataController1: NSObject, DataController {

    struct Section {
        let type: SectionTypeEnum
        let rows: [Any]
    }

    let contactData: ContactData
    var section1: [Section1]
    var section2: [Section2]
    var section3: [Section3]
    var sections: [Section]


    init(contactData: ContactData) {
        self.contactData = contactData

        section1 = self.contactData.list1
        section2 = self.contactData.list2
        section3 = self.contactData.list3
        sections = [Section(type: .section1, rows: section1),
                    Section(type: .section2, rows: section2),
                    Section(type: .section3, rows: section3)]
    }
}

您可以通过以下方式快速解决此问题：

words[x].include? != " "

完成整个事情的更好方法是：

!words[x] == " "

Answer 2

使用Array#chars。

'Words and stuff.'.chars.map { |c| c ==  " " ? "0" : c }
 #=> ["W", "o", "r", "d", "s", "0", "a", "n", "d", "0", "s", "t", "u", "f", "f", "."]

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