我有以下网址:http://0.0.0.0:3000/book/all?my_query
如何放弃所有?my_query"只留下"预订/"
我试着这样做:
if (this.$route.params.item === 'all') { this.$router.replace ('/') }
但它只返回主页
答案 0 :(得分:1)
删除所有参数:
this.$router.replace({'query': null});
添加my_query
param:
this.$router.replace({'query': {'my_query': 1}});
答案 1 :(得分:0)
只需删除查询对象的属性
Use webviewPlus---->
dependencies:
webview_flutter_plus: ^0.1.1+10
add traffic on android >> app >> src >> main >> AndroidManifest.xml
<application
android:usesCleartextTraffic="true">
</application>
Take these permission also on this Manifest file -------->
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.WAKE_LOCK" />
update ios info.plist----->
location-----------------> ios/Runner/Info.plist
<key>NSAppTransportSecurity</key>
<dict>
<key>NSAllowsArbitraryLoads</key> <true/>
</dict>
<key>io.flutter.embedded_views_preview</key> <true/>
Code like this
WebViewPlus(
javascriptMode: JavascriptMode.unrestricted,
onWebViewCreated: (controller) {
controller.loadString(r"""
<html lang="en">
<body>hello world</body>
</html>
""");
},
)
答案 2 :(得分:0)
这是解决方案:
$router.push($route.path)