我对akka世界有点新意,所以我的知识领域有点小。我正在创建一个https服务器并使用akka流和http处理它,对于特定的URL,我需要将文件发送回客户端。我怎样才能使用akka流来实现这一目标并避免使用akka路径。
def handleCall(request:HttpRequest):HttpResponse = {
logger.info("Request is {}",request)
val uri:String = request.getUri().path()
if(uri == "/download"){
val f = new File("/1000.txt")
logger.info("file download")
return HttpEntity(
//What should i put here if i want to return a text file.
)
}
答案 0 :(得分:4)
如果文件可能很大,那么在将其发送到客户端之前,您不希望将所有内容都消耗到内存中。这是通过纯粹基于流的解决方案解决的:
import scala.io
import akka.stream.scaladsl.Source
import akka.http.scaladsl.model.HttpEntity.{Chunked, ChunkStreamPart}
import akka.http.scaladsl.model.{HttpResponse, ContentTypes}
val fileContentsSource : (String, String) => Source[ChunkStreamPart, _] =
(fileName, enc) =>
Source
.fromIterator( io.Source.fromFile(fileName, enc).getLines )
.map(ChunkStreamPart.apply)
val fileEntityResponse : (String, String) => HttpResponse =
(fileName, enc) =>
HttpResponse(entity = Chunked(ContentTypes.`text/plain(UTF-8)`,
fileContentsSource(fileName, enc)))
现在您可以在不让服务器保留整个内容的情况下创建和发送HttpResponse:
val httpResp : HttpResponse = fileEntityResponse("/foo/log.txt", "UTF8")
答案 1 :(得分:1)
val str2 = scala.io.Source.fromFile("/tmp/t.log", "UTF8").mkString
val str = Source.single(ByteString(str2))
HttpResponse(entity = HttpEntity.Chunked.fromData(ContentTypes.`application/octet-stream`, str))
答案 2 :(得分:0)
阿卡Http路线
pathSingleSlash {
get {
complete(HttpEntity.fromFile(ContentTypes.`application/octet-stream`, new File(s"/home/shivam/sample.zip"))
}
}
卷曲请求
curl --output sample.zip http://localhost:8080/
从HttpEntity.scala复制
/**
* Returns either the empty entity, if the given file is empty, or a [[HttpEntity.Default]] entity
* consisting of a stream of [[akka.util.ByteString]] instances each containing `chunkSize` bytes
* (except for the final ByteString, which simply contains the remaining bytes).
*
* If the given `chunkSize` is -1 the default chunk size is used.
*/