Question

我正在尝试创建一对多关系，下面是我的yml sechma

Country:
    actAs:
        Timestampable: ~
        I18n:
            fields: [country_name]
    columns:
        country_code: { type: string(30), notnull:true, unique: true }
        country_name: { type: string(200), notnull:true }
        country_flag: { type: string(200), notnull: flase }
        created_by: {type: bigint, notnull: true }
        updated_by: {type: bigint, notnull: false }
    relations:
        sfGuardUser1: { local: created_by, foreign: id, class: sfGuardUser }
        sfGuardUser2: { local: updated_by, foreign: id, class: sfGuardUser }
City: 
    actAs: 
        Timestampable: ~
        I18n: 
            fields: [city_name]
    columns:
        city_name: { type: string(100), notnull: true }
        country_code: { type: integer, notnull: true }
        created_by: {type: bigint, notnull: true }
        updated_by: {type: bigint, notnull: false }        
    relations: 
        Country:
            local: country_code
            foreign: country_code
            class: Country
        sfGuardUser1: { local: created_by, foreign: id, class: sfGuardUser }
        sfGuardUser2: { local: updated_by, foreign: id, class: sfGuardUser }

我面临的问题是生成的sql。上面的yml正在构建两个表的约束，同时我只想为City表构建约束。知道我该怎么办？

此致

Answer 1

将foreign设置为id，因为默认情况下，Doctrine会将主键称为id，直到您在架构中手动设置它为止。另外，我会手动设置模式中的关系类型（或者在模型中，如@benlumney所述）：

relations: 
    Country:
        local: country_code
        foreign: id # or you can just skip this param in this case
        class: Country
        type: many
        foreignType: one

symfony 1.4 - doctrine - 模型模式中的关系

1 个答案: