Question

我从JSON API获取Pokemon数据，它显示任何Pokemon的值。这里的目的是获取数据，显示可以找到哪些游戏的口袋妖怪以及它们在游戏中找到的区域。

可通过其encounters键值访问。我对访问途径特别感兴趣：

['location_area'] ['name']和['version'] ['name']

作为一个很好的网址示例：https://pokeapi.co/api/v2/pokemon/183/encounters

问题是，遇到数组索引值是一个URL，我通过自己的Curl json函数访问它，它工作正常，但只给我数组数字索引值。

public function getPokemonLocation($searchTerm)
{

    /*
    Get the Pokemon via search term name
     */

    $url = $this->baseUrl.$searchTerm;
    $pokemonLocation = $this->getUrl($url);

    /* 
        $pokemonLocationUrl is the encounters subset i the array URL 
    */

    $pokemonLocationUrl =  $pokemonLocation['location_area_encounters'];
    $pokemonLocationEncounters = $this->getUrl('https://pokeapi.co/' . $pokemonLocationUrl);

    echo "<pre>";
    print_r($pokemonLocationEncounters);
    echo "</pre>";


     /* 
        Now grab the data needed from the name of location and what game regions they are from 
     */

    $pokemonAreaEncounterArea = array();
    $pokemonAreaEncounterGame = array();

      foreach($pokemonLocationEncounters as $key => $encounter)
      {
         $pokemonAreaEncounterArea[] = $encounter['location_area']['name'];
          $pokemonAreaEncounterGame[] = $encounter['version_details'][0]['version']['name'];
      }
        $pokemonLocationAndRegion = array_combine($pokemonAreaEncounterGame,$pokemonAreaEncounterArea);

        // print_r($pokemonLocationAndRegion);

        return  $pokemonLocationAndRegion;
 }

问题是，遇到数组索引值是一个URL，我通过自己的Curl json函数访问它，它工作正常，但只给我数组数字索引值。

我可以轻松获取数据，如上所示。 Howwever想要完全访问所有数组索引，而不仅仅是一个或少数几个数据。很想通过多个foreach来做到这一点，但宁愿干净地实现它。

编辑：这是上面的Poke APi链接的第二个例子，如果你得到504服务器错误 - https://jsoneditoronline.org/?id=73911ec678c850f9b1ff131ac7ee738c

Answer 1

根据你的json返回一个基于索引的数组，这就是你的代码应该如何工作。

public function getPokemonLocation($searchTerm) {

    /*
    Get the Pokemon via search term name
     */

    $url = $this->baseUrl . $searchTerm;
    $pokemonLocation = $this->getUrl($url);

    /*
        $pokemonLocationUrl is the encounters subset i the array URL
    */

    $pokemonLocationUrl = $pokemonLocation['location_area_encounters'];
    $pokemonLocationEncounters = $this->getUrl('https://pokeapi.co/' . $pokemonLocationUrl);

    echo "<pre>";
    print_r($pokemonLocationEncounters);
    echo "</pre>";

    $pokemonAreaEncounterArea = array();
    $pokemonAreaEncounterGame = array();

    /*
       Now grab the data needed from the name of location and what game regions they are from
    */

    for($i=0,$size=count($pokemonLocation);$i<$size;$i++) {
        $pokemonAreaEncounterArea[] = $pokemonLocation[$i]['location_area']['name'];
        $pokemonAreaEncounterGame[] = $pokemonLocation[$i]['version_details'][0]['version']['name'];
    }

    $pokemonLocationAndRegion = array_combine($pokemonAreaEncounterGame, $pokemonAreaEncounterArea);

    // print_r($pokemonLocationAndRegion);

    return $pokemonLocationAndRegion;
}

使其更清晰

    for($i=0,$size=count($pokemonLocation);$i<$size;$i++) {
        $pokemonAreaEncounterArea[] = $pokemonLocation[$i]['location_area']['name'];
        $pokemonAreaEncounterGame[] = $pokemonLocation[$i]['version_details'][0]['version']['name'];
    }

这将允许您遍历结果数组中的所有元素，并将它们放在$pokemonAreaEncounterArea和$pokemonAreaEncounterGame

的相应数组中的相同索引上

Answer 2

您可以在迭代时组合目标数据：

$array=json_decode($json,true);
foreach($array as $item){
    $result[$item['version_details'][0]['version']['name']]=$item['location_area']['name'];
}
var_export($result);

输出：

array (
  'diamond' => 'great-marsh-area-6',
  'platinum' => 'sinnoh-route-215-area',
  'heartgold' => 'mt-mortar-1f',
  'ruby' => 'hoenn-route-120-area',
  'emerald' => 'hoenn-safari-zone-expansion-south',
  'leafgreen' => 'four-island-area',
  'black-2' => 'route-22-area',
  'x' => 'kalos-route-3-area',
)

PHP迭代后续键值

2 个答案: