Question

我是rx java的新手，在下面的代码中，只要有异常，订阅者就会停止订阅数据。在这种情况下＆＃34; hello3＆＃34;永远不会打印。如何让订户继续接收数据？

public class ReactiveDataService
{
  public Observable<String> getStreamData()
  {
    return Observable.create(o -> {
        o.onNext("hello1");
        o.onNext("hello2");
        o.onError(new TimeoutException("Timed Out!"));
        o.onNext("hello3");
    });
  } 
}

Observable<String> watcher = new ReactiveResource().getData()
    .timeout(3, TimeUnit.SECONDS)
    .onErrorResumeNext(th -> {
        return Observable.just("timeout exception");
    });

    watcher.subscribe(
            ReactiveResource::callBack, 
            ReactiveResource::errorCallBack,
            ReactiveResource::completeCallBack
    );

public static Action1 callBack(String data)
{
    System.out.println("--" + data);
    return null;
}

public static void errorCallBack(Throwable throwable)
{
    System.out.println(throwable);      
}

public static void completeCallBack()
{
    System.out.println("On completed successfully");
}


private Observable<String> getData()
{
    return new ReactiveDataService().getStreamData();
}

Answer 1

RxJava最多只允许一个onError，这意味着流程的结束。如果您发现自己想要发出更多错误，可能与正常项目交错，则意味着您需要一个可以代表两者的数据类型，配对或记录类。 io.reactivex.Notification是一种选择。

public Observable<Notification<String>> getStreamData() {
    return Observable.create(o -> {
        o.onNext (Notification.createOnNext("hello1"));
        o.onNext (Notification.createOnNext("hello2"));
        o.onError(Notification.createOnError(new TimeoutException("Timed Out!")));
        o.onNext (Notification.createOnNext("hello3"));
        o.onComplete();
    });
}

即使在Observable - rxjava发生错误后仍继续订阅数据

1 个答案: