Question

您如何更换列表中某些项目的一部分？（Python 3.x）说我有一个列表：

x = ["part2keep removeMe", "saveme removeMe", "third length to throw it off removeMe", "element to save", "KeepThisPart"]

如果我只想删除“removeMe”部分，你会怎么做呢？到目前为止我有这个：

def replaceExampleA(x, y):
    for i in x:
        if i[len(i)-8:len(i)-1] == "removeMe":
            y.append(i[0: -12])
        else:
            y.append(i)

编辑：刚刚意识到我犯了一个错误 - 列表更像是这样的： x = ["part2keep removeMe 123", "saveme removeMe 12", "third length to throw it off removeMe 83", "element to save", "KeepThisPart"]

我需要从“removeMe”元素中删除数字。感谢

Answer 1

x = [s.replace('removeMe', '') for s in x]

Answer 2

这可以通过列表理解来实现

x = ["part2keep removeMe", "saveme removeMe", "third length to throw it off removeMe"]

print(y.replace(' removeMe', '') for y in x)

Answer 3

您可以使用正则表达式来确保代码始终只在字符串末尾出现removeMe时才会被删除：

import re
x = ["part2keep removeMe", "saveme removeMe", "third length to throw it off removeMe", "element to save", "KeepThisPart"]
new_x = [re.sub('\sremoveMe$', '', i) for i in x]

输出：

['part2keep', 'saveme', 'third length to throw it off', 'element to save', 'KeepThisPart']

Answer 4

您也可以使用map功能

new_x = map(lambda e: e.replace('removeMe', ''), x)

这样做的好处就是你得到了一台发电机。因此在某些情况下，这会更有效。如果你想要一个列表，就像其他答案一样，那么你需要将它转换回一个列表

new_x = list(new_x)

如何替换列表中特定元素的某些部分？

4 个答案: