Question

所以即时编写我从scholl得到的python脚本测试但由于某种原因它甚至没有开始...没有错误没有什么... 它应该是和雇用日志系统..使用线程为无限循环，应该计算min和创建检查时钟为“雇用”并在后台运行和另一个功能，如果他已经签署，则支持阅读雇用名称检查在或不，如果没有将他添加到具有时钟时间和名称的文件或相反的方式，将他注销但由于某种原因代码甚至运行，没有错误，没有什么只是空白运行屏幕，生病了很高兴得到一些帮助..

#!/bin/usr/python
from datetime import datetime
import threading
import time
users=open("logfile.txt","w")
def background():
    seconde = 0
    minute = 0
    hour = 0
    while True:
        time.sleep(1)
        seconde = seconde + 1
        if seconde == 60:
            minute = minute + 1
            seconde = 0
        elif minute == 60:
                hour = hour + 1
                minute = 0
        alltime = str(hour) + ":" + str(minute) + ":" + str(seconde)
def foreground():
    alin = []
    name = input("Hello Deal employ , please insert your name:\n")
    if name not in alin:
        login=input("your not logged in , do you wish to log?\n")
        if login == "yes" or "Y" or "y" or "Yes":
            users.write("{} Entry Hour :".format(name) + alltime)
            alin.append(name)
        elif login == "no" or "N" or "n" or "No":
                print("ok") and exit()
    elif name in alin:
        logout=input("Your allready signed in , do you wish to check out?\n")
        if logout == "Yes" or "Y" or "Y" or "yes":
            users.write("{} Leaving Hour :".format(name) + alltime)
        elif logout == "no" or "N" or "n" or "No":
            print("ok") and exit()


b = threading.Thread(name='background', target=background())
a = threading.Thread(name='foreground', target=foreground())

b.start()
a.start()

Answer 1

b = threading.Thread(name='background', target=background())

target应该是一个可调用的对象。在启动线程之前，您正在运行background。由于background永不停止，您的程序将永远运行。尝试：

b = threading.Thread(name='background', target=background)

我不确定你要做什么，但我很确定它不会起作用。

在python中使用log in hours脚本

1 个答案: