Question

我是android的新手，我在下面给出了结构中的json。如何使用json解析或改造来解析？

{
   "1,abcd":[{
                 "v_id":"1"
               }]
   "2,efgh":[{
                 "v_id":"2"
               }]
}

Answer 1

试试这个

try {
           JSONObject jsonObject = new JSONObject("yourresponce");
           JSONArray jsonarray = jsonObject.getJSONArray("1,abcd");


           for(int i=0;i<jsonarray.length();i++){
               JSONObject jsonObject1 = jsonarray.getJSONObject(i);
               String   v_id  = jsonObject1.getString("v_id");
               Log.d("seelogcat","values   "+v_id);

           }

           JSONArray jsonarray2 = jsonObject.getJSONArray("2,efgh");


           for(int i=0;i<jsonarray2.length();i++){
               JSONObject jsonObject1 = jsonarray2.getJSONObject(i);
               String   v_id  = jsonObject1.getString("v_id");
               Log.d("seelogcat","values   "+v_id);

           }

       }catch (Exception e){

       }

您的json格式无效：您的格式应该低于此

{
    "1,abcd": [{
        "v_id": "1"
    }],     // here you have to add (,)
    "2,efgh": [{
        "v_id": "2"
    }]
}

您可以在此查看您的Json是否有效https://jsonlint.com/

要将密钥分开：

Iterator<?> keys = response.keys();
while( keys.hasNext() ) {
    String key = (String)keys.next();
    if ( jObject.get(key) instanceof JSONObject ) {
        System.out.println(key); // here you need splint based on (,)
    }
}

Answer 2

那里有一个逗号（，）丢失。签入jsonlint

{
    "1,abcd": [{
        "v_id": "1"
    }],
    "2,efgh": [{
        "v_id": "2"
    }]
}

Gson的改造可以完成剩下的工作。响应的POJO如下：

public class Example {

@SerializedName("1,abcd")
@Expose
private List<_1Abcd> Abcd = null;
@SerializedName("2,efgh")
@Expose
private List<_2Efgh> Efgh = null;

public List<_1Abcd> get1Abcd() {
return Abcd;
}

public void set1Abcd(List<_1Abcd> Abcd) {
this.Abcd = Abcd;
}

public List<_2Efgh> get2Efgh() {
return Efgh;
}

public void set2Efgh(List<_2Efgh> Efgh) {
this.Efgh = Efgh;
}

}

和

public class _1Abcd {

@SerializedName("v_id")
@Expose
private String vId;

public String getVId() {
return vId;
}

public void setVId(String vId) {
this.vId = vId;
}

}

和

public class _2Efgh {

@SerializedName("v_id")
@Expose
private String vId;

public String getVId() {
return vId;
}

public void setVId(String vId) {
this.vId = vId;
}

}

如何在android中解析具有特殊字符的json对象

2 个答案: