Question

虽然我没有成功使用php路由，因为超出了我目前的知识，我尝试了下面的实现：

$query = "SELECT * FROM persons WHERE SURNAME LIKE 'Ω%' ORDER BY SURNAME ASC;";
$result = mysqli_query($con, $query); //the selected query has 2 results!

/* determine number of rows result set */
$row_cnt = mysqli_num_rows($result);

printf("results (%d).", $row_cnt);

// Check result
// This shows the actual query sent to MySQL, and the error. Useful for debugging.
if (!$result) {
    $message  = 'Invalid query: ' . mysqli_error($con) . "\n";
    $message .= 'Whole query: ' . $query;
    die($message);
}

function generateTableFromResult($result) {
    $x = 1;
    $html = "<table>";
    while($row = mysqli_fetch_array($result)) {
        foreach($row as $column => $value) {
            copy("persons.php","newfile".$x.".php");
            $html.="<tr><th>".$column."</th><td>".$value."</td></tr>";
            $myfile = fopen("newfile".$x.".php", "w") or die("Unable to open file!");
            fwrite($myfile, $html);
        }
        $x++;
    }
    $html .= "</table>";
    return $html;
}

// usage:
// ...
$result = mysqli_query($con, $query);
echo generateTableFromResult($result);`

以上脚本创建：

newfile1.php --> table + table (first + second result)
newfile2.php --> table + table (first + second result)

虽然我想要：

newfile1.php --> table (first result)
newfile2.php --> table (second result)

我在这里缺少什么？

编辑：

newfile1.php的示例内容：

CODE_NO 12101 SURNAME ΩΝΑΣΗ FIRST_NAME ΧΡΙΣΤΙΝΑ SOURCE1 ΗΛΙΟΥ SOURCE2 SOURCE3 PROV ΟΙΚΟΓΕΝΕΙΑΚΗ ΣΧΕΣΗ ΚΑΘΕΤΗ ΜΕ ΚΙΝΗΤΙΚΟΤΗΤΑ SEX ΓΥΝΑΙΚΑ BIRTH 1950 DEATH 1989 PLACE ΜΕΓΑΛΟ ΑΣΤΙΚΟ ΚΕΝΤΡΟ REGION ΑΛΛΕΣ ΞΕΝΕΣ ΧΩΡΕΣ EDUCATION ΜΕΤΑΠΤΥΧΙΑΚΕΣ ΣΠΟΥΔΕΣ SPECIAL WRITING POLITICAL MANAGERIAL MILITARY RELIGIOUS SPIRITUAL SCIENTIFIC NOBLE ΝΑΙ CULTURAL FINANCIAL ΝΑΙ CONSTITUTIONAL OPPOSITION PROF1 Επιχειρηματίας PROF2 Νεώτερη αριστοκρατική ελίτ πλουτου PROF3 PROF4 PROF5 PARTY ACTIVITY1 ACTIVITY2 1800_1832 1833_1862 1863_1911 1912_1922 1923_1944 1945_1973 ΝΑΙ 1974_ ΝΑΙ HIERARCHY Ανωτάτη Ελίτ LEADERSHIP

HERE启动表2 这就是表格的样子。请记住，我希望每个人/文件都能写出每个表。

CODE_NO 12100 SURNAME ΩΝΑΣΗΣ FIRST_NAME ΑΡΙΣΤΟΤΕΛΗΣ SOURCE1 ΗΛΙΟΥ SOURCE2 ΔΡΑΝΔΑΚΗ SOURCE3 ΕΚΔΟΤΙΚΗ PROV ΑΓΝΩΣΤΗ SEX ΑΝΔΡΑΣ BIRTH 1906 DEATH 1975 PLACE ΑΓΡΟΤΙΚΕΣ- ΝΗΣΙΩΤΙΚΕΣ REGION ΜΙΚΡΑ ΑΣΙΑ EDUCATION ΔΕΝ ΔΗΛΩΝΕΙ SPECIAL WRITING POLITICAL MANAGERIAL MILITARY RELIGIOUS SPIRITUAL SCIENTIFIC NOBLE ΝΑΙ CULTURAL FINANCIAL ΝΑΙ CONSTITUTIONAL OPPOSITION PROF1 Εφοπλιστής PROF2 Νεώτερη αριστοκρατική ελίτ πλουτου PROF3 PROF4 PROF5 PARTY ACTIVITY1 ACTIVITY2 1800_1832 1833_1862 1863_1911 1912_1922 1923_1944 ΝΑΙ 1945_1973 ΝΑΙ 1974_ HIERARCHY Yψιστη Μορφή Ελίτ LEADERSHIP

Answer 1

这应该产生你想要的输出（来自你的评论）：

function generateTableFromResult($result) {
    $x    = 1;
    $html = '';
    while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
        // Add the open-table tag
        $html = '<table>';

        // Iterate through the columns and add them to our variable
        foreach($row as $column => $value) {
            $html .= "<tr><th>".$column."</th><td>".$value."</td></tr>";
        }

        // Add the close-table tag
        $html .= "</table>";

        // Now, since we've added all the rows for that person, 
        // create, populate and store the file
        file_put_contents("newfile".$x.".php", $html);

        // Increment $x before we jump to the next person
        $x++;
    }

    // However, this will only return the table for the last person
    return $html;
}

我还将您的fopen和copy（实际上没有用）更改为一个简单的命令：file_put_contents()

对@ishegg大吼大叫帮助缩小了问题范围

Answer 2

默认情况下，mysqli_fetch_array()的获取模式为MYSQLI_BOTH，这意味着它会以关联的和数字格式获取每个结果。除了对结果进行双循环外，还可以为您提供结果。

要解决此问题，您可以使用MYSQLI_ASSOC（或使用mysqli_fetch_assoc()），因此每行只会获得一次。

function generateTableFromResult($result) {
    $x = 1;
    $html = "<table>";
    while($row = mysqli_fetch_assoc($result)) {
        foreach($row as $column => $value) {
            copy("persons.php","newfile".$x.".php");
            $html.="<tr><th>".$column."</th><td>".$value."</td></tr>";
            $myfile = fopen("newfile".$x.".php", "w") or die("Unable to open file!");
            fwrite($myfile, $html);
        }
    $x++;
    }
    $html.="</table>";
    return $html;
}

或者，保持原有的功能：

function generateTableFromResult($result) {
    $x = 1;
    $html = "<table>";
    while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
        foreach($row as $column => $value) {
            copy("persons.php","newfile".$x.".php");
            $html.="<tr><th>".$column."</th><td>".$value."</td></tr>";
            $myfile = fopen("newfile".$x.".php", "w") or die("Unable to open file!");
            fwrite($myfile, $html);
        }
    $x++;
    }
    $html.="</table>";
    return $html;
}

另外，正如@MagnusEriksson指出的那样，您每次都会将内容附加到$html，因此您仍然可以在第二个文件中获得这两个结果。为避免这种情况，请将$html = "table";放在foreach循环中：

function generateTableFromResult($result) {
    $x = 1;
    while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
        foreach($row as $column => $value) {
            copy("persons.php","newfile".$x.".php");
            $html = "<table>";
            $html.="<tr><th>".$column."</th><td>".$value."</td></tr>";
            $html.="</table>";
            $myfile = fopen("newfile".$x.".php", "w") or die("Unable to open file!");
            fwrite($myfile, $html);
        }
        $x++;
    }
    return $html;
}

php中的foreach循环需要调试

2 个答案: