Question

我有一个MySQL数据库，其中有一个名为'posts'的表我正在通过FeathersJS和feathers-sequelize阅读。目前我有一个使用以下代码的工作原型，它返回所需的结果，但仅返回到控制台，以及posts表到/ posts路由的全部内容，但是我只想从表中返回一组特定的记录到/帖子。

该表有一个名为post_status的列，其中帖子可以是“已发布”或“草稿”。我只想将'已发布'的记录返回到/ posts，但是想要实现这个服务器端而不是/ posts？status = published。如何实现这一目标？

见下面的代码：

const path = require('path');
const feathers = require('@feathersjs/feathers');
const express = require('@feathersjs/express');
const socketio = require('@feathersjs/socketio');

const Sequelize = require('sequelize');
const service = require('feathers-sequelize');

const sequelize = new Sequelize('sandbox', 'sandbox', 'secretpassword', {
  host: 'localhost',
  dialect: 'mysql',

  pool: {
    max: 5,
    min: 0,
    acquire: 30000,
    idle: 10000
  },

  operatorsAliases: false
});

const Post = sequelize.define('posts', {
  post_title: Sequelize.STRING
},
{
  timestamps: false,
  underscored: true,
});

// Create an Express compatible Feathers application instance.
const app = express(feathers());

// Turn on JSON parser for REST services
app.use(express.json());
// Turn on URL-encoded parser for REST services
app.use(express.urlencoded({ extended: true }));
// Enable REST services
app.configure(express.rest());
// Enable Socket.io services
app.configure(socketio());


app.use(express.errorHandler());

//This works fine to return to the console but not to /posts
Post.findAll({
where: {
  post_status: 'published'
}
}) .then(posts => {
    console.log(JSON.stringify(posts));
  });

//This returns the entire contents of the posts table to /posts
app.use('/posts', service({
  Model: Post,
  paginate: {
    default: 10,
    max: 100
  },
}));

// Start the server
const port = 3030;

app.listen(port, () => {
  console.log(`Feathers server listening on port ${port}`);
});

我尝试了服务中findAll方法的'where'，但这并没有改变输出，也没有产生任何错误。

Answer 1

我通过在服务的find方法中使用where子句解决了这个问题，请参阅下面的完整代码：

{{1}}

FeathersJS REST返回具有特定值

1 个答案: