Question

我正在尝试遍历一个长列表（让我们称之为url_list），其中每个项目都是这样的：

<a href="https://www.example.com/5th-february-2018/" itemprop="url">5th February 2018</a>, <a href="https://www.example.com/4th-february-2018/" itemprop="url">4th February 2018</a>, <a href="https://www.example.com/3rd-february-2018/" itemprop="url">3rd February 2018</a>, <a href="https://www.example.com/2nd-february-2018/" itemprop="url">2nd February 2018</a>,

等等。我想迭代列表，只保留前两个引号之间的文本，然后扔掉其余的 - 即：

https://www.example.com/5th-february-2018/, https://www.example.com/4th-february-2018/, https://www.example.com/3rd-february-2018/, https://www.example.com/2nd-february-2018/,

所以基本上我试图返回一个很好的清洁网址列表。我没有太多的运气迭代列表和分割引号 - 是否有更好的方法来做到这一点？有没有办法丢弃itemprop=字符串之后的所有内容？

Answer 1

使用正则表达式：

import re

url_list = ['<a href="https://www.example.com/5th-february-2018/" itemprop="url">5th February 2018</a>', '<a href="https://www.example.com/4th-february-2018/" itemprop="url">4th February 2018</a>']
for i in url_list:
    print re.search("(?P<url>https?://[^\s]+)/", i).group("url")

<强>输出：

https://www.example.com/5th-february-2018
https://www.example.com/4th-february-2018

Answer 2

您是否尝试过使用拆分功能拆分＆＃34;然后从结果列表中获取第二个条目？

urls=[]
for url_entry in url_list:
    url = url_entry.split('\"')[1]
    urls.append(url)

Answer 3

这听起来有点像XY problem。

如果您（或正在）使用BeautifulSoup来解析HTML，那将变得更加轻松：

from bs4 import BeautifulSoup

html_text = '''<a href="https://www.example.com/5th-february-2018/" itemprop="url">5th February 2018</a>
<a href="https://www.example.com/4th-february-2018/" itemprop="url">4th February 2018</a>
<a href="https://www.example.com/3rd-february-2018/" itemprop="url">3rd February 2018</a>
<a href="https://www.example.com/2nd-february-2018/" itemprop="url">2nd February 2018</a>'''

soup = BeautifulSoup(html_text)
urls = [x['href'] for x in soup.find_all("a")]
for url in urls:
    print(url)
# https://www.example.com/5th-february-2018/
# https://www.example.com/4th-february-2018/
# https://www.example.com/3rd-february-2018/
# https://www.example.com/2nd-february-2018/

如何使用Python 2.7.10遍历列表并在引号之间提取文本

3 个答案: