我有一个程序，它读入一个简单的JSON文件并操纵数据。然后我将这些数据存储在树中（虽然很糟糕）。我有一个问题，其中参数可以长，例如{1,2}，长整数和变量，例如{1，x2}，或变量与其他变量，例如{X1，X2}。
我已经能够从JSONArray中检索变量。当我有变量和值时会出现问题。我不能为我的生活弄清楚如何处理这样的事情。我为过度使用try-catch操作道歉。如果有人能帮我解决这个问题，我将不胜感激。
public class program {
public static void main(String[] args) throws IOException {
File file = new File();
File outputfile = new File();
PrintWriter pw = new PrintWriter(new BufferedWriter(new
FileWriter(outputfile, true)));
JSONParser parser = new JSONParser();
try {
// creates object of parsed file
Object object = parser.parse(new FileReader(file));
// casts object to jsonObject
JSONObject jsonObject = (JSONObject) object;
// gets declaration-list JSONArray from the object created.
JSONArray jsonArray = (JSONArray) jsonObject.get("declaration-list");
// Surrounding this in a try-catch would allow me to deal with the
// different value cases unlike the frist time i wrote it
try {
/*
* iterator to cycle through the array. Made the mistake last
* time of continuously calling a method
*/
Iterator iterator = jsonArray.iterator();
while (iterator.hasNext()) {
JSONObject jo = (JSONObject) iterator.next();
String variableName = (String) jo.get("declared-variable");
MyTreeNode<String> root = new MyTreeNode<>(variableName);
try {
long value = (long) jo.get("value");
MyTreeNode<Long> child1 = new MyTreeNode(value);
System.out.println(root.getData());
root.addChild(child1);
for (MyTreeNode node : root.getChildren()) {
System.out.println(node.getData());
}
test.put(variableName, value);
// numPrint(test, variableName, pw);
} catch (Exception e) {
final JSONObject jsonValue = (JSONObject) jo.get("value");
final String operator = (String) jsonValue.get("operator");
final JSONArray arguments = (JSONArray) jsonValue.get("arguments");
ArrayList values[] = new ArrayList[arguments.size()];
if (operator.equals("set")) {
for(int i = 0; i < arguments.size(); i++){
try{
//prints nested variables
JSONObject jtest = (JSONObject) arguments.get(i);
String varval = (String) jtest.get("variable");
System.out.println(varval);
}catch(Exception g){
}
}
MyTreeNode<myObject> test1 = new MyTreeNode(new myObject(operator, arguments));
root.addChild(test1);
for (MyTreeNode node : root.getChildren()) {
System.out.print(root.getData());
System.out.print(" = ");
System.out.println(node.getData());
}
}
if (operator.equals("pair")) {
MyTreeNode<myObject> test1 = new MyTreeNode(new myObject(operator, arguments));
root.addChild(test1);
for (MyTreeNode node : root.getChildren()) {
System.out.print(root.getData() + " = ");
System.out.println(node.getData());
}
}
}
}
} catch (Exception e) {
System.out.println("oops");
}
} catch (FileNotFoundException e) {
System.out.println("Input file not found");
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (ParseException e) {
System.out.println("File was not parsed");
e.printStackTrace();
}
pw.flush();
pw.close();
}
}
class MyTreeNode<T> {
private T data = null;
private List<MyTreeNode> children = new ArrayList<>();
private MyTreeNode parent = null;
public MyTreeNode(T data) {
this.data = data;
}
public void addChild(MyTreeNode child) {
child.setParent(this);
this.children.add(child);
}
public void addChild(T data) {
MyTreeNode<T> newChild = new MyTreeNode<>(data);
newChild.setParent(this);
children.add(newChild);
}
public void addChildren(List<MyTreeNode> children) {
for (MyTreeNode t : children) {
t.setParent(this);
}
this.children.addAll(children);
}
public List<MyTreeNode> getChildren() {
return children;
}
public T getData() {
return data;
}
public void setData(T data) {
this.data = data;
}
private void setParent(MyTreeNode parent) {
this.parent = parent;
}
public MyTreeNode getParent() {
return parent;
}
}
class myObject {
String operator;
JSONArray arguments;
public myObject(String operator, JSONArray arguments) {
this.operator = operator;
this.arguments = arguments;
}
public JSONArray get() {
return arguments;
}
public String toString() {
if (arguments.size() == 0) {
return "{}";
}
if (operator.equals("pair")) {
return "(" + arguments.get(0) + "," + arguments.get(1) + ")";
} else if (operator.equals("set")) {
String concat = "{" + arguments.get(0);
for (int i = 1; i < arguments.size(); i++) {
concat += "," + arguments.get(i);
}
return concat += "}";
}
return "wot";
}
}
答案 0 :(得分：1)
为了处理JSONArray，我建议您先创建一个检查对象类型的方法，然后根据其类型将处理委托给其他专门方法。
这将允许您重复使用代码，以防您在数组中有数组并且还可以浏览JSON树。
这些方面的东西：
private static void processArray(JSONArray jsonArray) {
jsonArray.forEach(o -> {
if (o instanceof Number) {
processNumber((Number) o);
} else if (o instanceof JSONObject) {
process((JSONObject) o);
} else if (o instanceof String) {
process((String) o);
} else if (o instanceof JSONArray) {
processArray((JSONArray) o); // recursive call here.
}
});
}
其他方法如下：
private static void process(String o) {
System.out.println(o); // just an example
}
public static void processNumber(Number number) {
System.out.println(number); // just an example
}
最复杂的是处理对象的那个：
private static void process(JSONObject o) {
o.forEach((s, o1) -> {
System.out.println(s);
if (o1 instanceof Number) {
processNumber((Number) o1);
} else if (o1 instanceof JSONObject) {
process((JSONObject) o1); // recursion
} else if (o1 instanceof String) {
process((String) o1);
} else if (o1 instanceof JSONArray) {
processArray((JSONArray) o1);
}
});
}
此方法也是递归的。使用这种方法，您可以浏览树中的所有对象。
<强>更新
如果您想处理JSON，请执行以下操作：
{
"declared-variable": "x17",
"value": {
"operator": "set",
"arguments": [
1,
2,
{
"variable": "x8"
}
]
}
}
你可以通过创建一个类似于这个的主方法来实现：
public static void main(String[] args) throws IOException, ParseException {
JSONParser jsonParser = new JSONParser(JSONParser.MODE_JSON_SIMPLE);
try (InputStream in = Thread.currentThread().getContextClassLoader().getResourceAsStream("array_mixed.json")) {
Object obj = jsonParser.parse(in);
if (obj instanceof JSONArray) {
processArray((JSONArray) obj);
}
else if(obj instanceof Object) {
process((JSONObject) obj);
}
}
}
这个主要方法与所描述的其他方法一起至少可以打印出JSON中的所有元素。
在上面指定的JSON的情况下，您应该能够至少打印出以下内容：
declared-variable
x17
value
arguments
1
2
variable
x8
operator
set