Question

我有两种用户类型：操作和维护。维护用户类型可以访问Operations用户类型的所有路由，但操作无法访问维护所有的所有路由。

这是我现有的代码。

Route::group(['middleware'=>'maintenance'], function(){
    //routes here

    Route::group(['middleware'=>'operations'], function(){
         //routes here

    });
});

kernel.php

 protected $routeMiddleware = [
    'auth' => \Illuminate\Auth\Middleware\Authenticate::class,
    'auth.basic' => \Illuminate\Auth\Middleware\AuthenticateWithBasicAuth::class,
    'bindings' => \Illuminate\Routing\Middleware\SubstituteBindings::class,
    'can' => \Illuminate\Auth\Middleware\Authorize::class,
    'guest' => \App\Http\Middleware\RedirectIfAuthenticated::class,
    'throttle' => \Illuminate\Routing\Middleware\ThrottleRequests::class,
    'revalidate' => \App\Http\Middleware\RevalidateBackHistory::class,
    'dev' => \App\Http\Middleware\isDev::class,
    'operations' => \App\Http\Middleware\operations::class,
    'maintenance' => \App\Http\Middleware\maintenance::class,
];

中间件/ operations.php

public function handle($request, Closure $next)
{
    $a = UserAccess::where(['employee_id'=>\Auth::user()->id, 'user_type_id'=>1])->first();
    if($a){
        return $next($request);
    }

    return redirect('/');
}

但它不起作用。维护可以访问其所有路由，但无法访问操作，操作根本无法访问任何路径。

注意：两个组都在auth中间件组

中

Answer 1

为此找到了解决方法。我创建了另一个中间件，它通过将两个参数传递给该中间件来满足操作和维护，特别是1 =操作和2 =维护，并检查了中间件访问。这是代码：

Route::group(['middleware'=>'access:2,2'], function(){
    //Routes that can be accessed by Maintenance user type
});

Route::group(['middleware'=>['access:1,2']], function(){
    //Routes that can be accesed by Operations and Maintenance user type.
});

这是中间件：

public function handle($request, Closure $next, $ops, $main)
{
    $a = UserAccess::where('employee_id',\Auth::user()->id)->whereIn('user_type_id', [$ops, $main])->first();
    if($a){
        return $next($request);
    }

    return redirect('/');
}

修改

优化代码以消除参数冗余。

Web.php：

Route::group(['middleware'=>'access:2'], function(){ //Routes that can be accessed by Maintenance user type }); Route::group(['middleware'=>['access:1,2']], function(){ //Routes that can be accesed by Operations and Maintenance user type. });

access.php

public function handle($request, Closure $next, $ops, $main = 0) { $a = UserAccess::where('employee_id',\Auth::user()->id)->whereIn('user_type_id', [$ops, $main])->first(); if($a){ return $next($request); } return redirect('/'); }

Answer 2

我认为您错过了where查询中的其他数组，请尝试更改operations中间件中的代码，如下所示：

$a = UserAccess::where([
         ['employee_id', \Auth::user()->id],
         ['user_type_id', 1]
     ])->first();

修改

然后尝试将middlewares移动到$middlewareGroups web中间件之下，如下所示：

'web' => [ ... ], 'operations' => \App\Http\Middleware\operations::class, 'maintenance' => \App\Http\Middleware\maintenance::class,

编辑2：

将$a变量的代码更改为此

$a = UserAccess::where([ ['employee_id', Auth::user()->id], //Hence there is no \ before Auth ['user_type_id', 1] ])->first();

然后在该文件的顶部包含以下use：

use Illuminate\Support\Facades\Auth;

编辑3：

您可以向request添加其他参数，然后向前发送，如下所示：

<强>中间件/ operations.php

function handle($request, Closure $next) { ... $request->attributes->add(['passedOperations' => true]); return next($next); }

<强>中间件/ maintenance.php

function handle($request, Closure $next) { ... if($request->get('passedOperations')) { return next($next); } else { //didn't pass operations } }

Laravel 5.5多用户类型嵌套路由组

2 个答案: