我有一张桌子可以跟踪游戏中玩家和每个服务器的加入和离开事件。我遇到的问题是,我如何知道谁离线以及谁在线?
这是我的表格结构,以及一些示例值:
CREATE TABLE `b_rbx_connections` (
`id` int(11) NOT NULL,
`server` varchar(48) NOT NULL,
`place` int(11) NOT NULL,
`player` int(11) NOT NULL,
`type` enum('join','leave') NOT NULL,
`followed` int(11) DEFAULT NULL COMMENT '0/null=none',
`time` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
INSERT INTO `b_rbx_connections` (`id`, `server`, `place`, `player`, `type`, `followed`, `time`) VALUES
(1, '83889ac4-eaf9-45af-8b9d-fa1b14dba952', 1253620452, 50180001, 'join', NULL, '2018-02-10 06:04:30'),
(2, '83889ac4-eaf9-45af-8b9d-fa1b14dba952', 1253620452, 50180001, 'leave', NULL, '2018-02-10 06:32:27'),
(3, '9f1aabe0-e314-46f1-bb81-c45ea70fdae9', 1253620452, 50180001, 'join', NULL, '2018-02-11 22:54:53');
每次玩家加入行时都会插入服务器ID,地址ID,无论是加入还是离开,以及活动时间。
这是我到目前为止所尝试的,但它只适用于每个玩家只加入/离开一次:
$q = "SELECT DISTINCT player FROM `b_rbx_connections` WHERE place='$placeId' AND type='join' AND time <= '$timestamp' ORDER BY `time` DESC";
$j = $db->query($q);
$q = "SELECT DISTINCT player FROM `b_rbx_connections` WHERE place='$placeId' AND type='leave' AND time <= '$timestamp' ORDER BY `time` DESC";
$l = $db->query($q);
$this->players = $j->fetchAll(PDO::FETCH_COLUMN, 0);
$this->offline_players = $l->fetchAll(PDO::FETCH_COLUMN, 0);
$this->online_players = array_diff($this->players, $this->offline_players);
输出:
{
"players": [
"50180001"
],
"offline_players": [
"50180001"
],
"online_players": [
]
}
但它应该是。
{
"players": [
"50180001"
],
"offline_players": [
],
"online_players": [
"50180001"
]
}
注意:一个地方是游戏ID,服务器是该游戏中服务器的实例ID,而玩家是该玩家的id。
答案 0 :(得分:1)
您应该在搜索中对播放器进行分组,以获得每个播放器的“最新”状态。然后使用该新数组来解析所需的结果。
SELECT *
FROM (Select * FROM `b_rbx_connections` order by time desc) as results
GROUP BY player
查看http://sqlfiddle.com/#!9/fd03cb/3/0,我添加了更多播放器来测试查询。
答案 1 :(得分:0)
select p.player, (
select c.type
from b_rbx_connections c
where c.player = p.player
and c.place = 1253620452
order by c.time desc
limit 1
) as type
from b_rbx_players p
这将返回给定type
的连接表中所有玩家和最后一行的place
。如果播放器没有条目,type
将为NULL(可以认为是离线)。
现在使用PHP循环将玩家分配到不同的阵列。