我对Android开发很新。有人可以让我知道动态更新TextView
(或整个屏幕)的相关API吗?
例如:我有一个搜索应用程序,我需要显示结果,而不是等待所有结果然后显示。
答案 0 :(得分:22)
有几个步骤,你没有提到你知道多少你不知道多少。
假设您的UI初始结构是在res / layout中定义的,并且它在您的活动中包含TextView:
public void updateTextView(String toThis) {
TextView textView = (TextView) findViewById(R.id.textView);
textView.setText(toThis);
}
答案 1 :(得分:3)
如果您要将新文本设置为TextView
,只需调用textView.setText(newText)
,其中newText是更新后的文本。每当newText发生变化时调用此方法。那是你在找什么?
答案 2 :(得分:2)
首先,您需要一个列表视图,所以
private volatile ArrayList<String> searchResults;
ListView searchList = (ListView) findViewById(R.id.listYOURLISTVIEW);
listAdapter = new ArrayAdapter<String>(this, R.layout.blacklist, R.id.list_content, searchResults); //blacklist is a layout to paint the fonts black
searchList.setAdapter(listAdapter);
这可能有所帮助。
private Thread refreshThread;
private boolean isRefreshing = false;
private void reinitializeRefreshThread()
{
if (!refreshThread.equals(null)) refreshThread.stop();
Log.d(LOGTAG+"::reinitializeRefreshThread()", "Creating new thread!\n");
isRefreshing = true;
refreshThread = (new Thread(new Runnable()
{
public void run()
{
Looper.prepare();
while (isRefreshing)
{
//GRAB YOUR SEARCH RESULTS HERE
//make sure the methods are synchronized
//maybe like
String[] results = grabResults(); //doesn't need to be synchronized
addResultList(results);
Message message = myHandler.obtainMessage();
myHandler.sendMessage(message);
try
{
Thread.sleep(2000);
} catch (InterruptedException e)
{
e.printStackTrace();
}
Log.d(LOGTAG+"->refreshThread", "Refresh finished!\n");
}
}
}));
Log.d(LOGTAG+"::reinitializeRefreshThread()", "Refresh thread started!\n");
refreshThread.start();
}
final Handler myHandler = new Handler()
{
public void handleMessage(android.os.Message msg)
{
listAdapter.notifyDataSetChanged();
};
};
,其中
public synchronized void addResultList(String[] results)
{
// remove the whole list, repopulate with new data
searchResults.clear();
for (int i = 0; i < results.length; i++)
{
addResult(results[i]);
}
}
private synchronized void addResult(CharSequence result)
{
if (!searchResults.contains(result.toString()))
searchResults.add(result.toString());
else
Toast.makeText(getApplicationContext(), "Result " + result.toString() + " was already on the list!", Toast.LENGTH_SHORT).show();
}
所有这些都是线程安全的,这意味着它允许您通过将消息发送到UI需要更新的主线程来从主线程以外的线程“更改”GUI。如您所见,refreshThread更新搜索集合(确保方法已同步),然后通知主(UI)线程更新列表。
您可能会觉得这也很有用
searchList.setOnItemClickListener(new AdapterView.OnItemClickListener()
{
public void onItemClick(AdapterView<?> arg0, View arg1, int arg2, long arg3)
{
listIndex = arg2;
selectedItem = (String) searchList.getItemAtPosition(listIndex);
Toast.makeText(getApplicationContext(), "Result[" + listIndex + "] " + selectedItem + " selected!", Toast.LENGTH_SHORT).show();
}
});
可能有一些松散的结局,比如你需要初始化listIndex和selectedItem或者只是把它们扔掉,但总的来说这在我非常类似的情况下为我做了伎俩(我有一个后台线程填充列表新条目的时间)
希望有所帮助:)
答案 3 :(得分:1)
尝试这个
TextView textView = (TextView)findViewById(R.id.textViewID);
textView.setText("The test you need");
view.invalidate(); // for refreshment
答案 4 :(得分:0)
如果您在另一个线程中,请确保更新UI线程内的textview。
private void updateTextView(final String s) {
MainActivity.this.runOnUiThread(new Runnable() {
@Override
public void run() {
TextView tv= (TextView) findViewById(R.id.tv);
tv.setText("Text = "+s);
}
});
}