Question

作为课程的一部分，我必须以天为单位定义年龄。前三部分正在工作，但最后一部分不工作。因为我必须在上一个函数中导入今天的两个日期（age_in_days）和日期。任何人都可以解释这是如何工作的

import datetime
def days_in_month(year, month):
    """
    Inputs:
      year  - an integer between datetime.MINYEAR and datetime.MAXYEAR
              representing the year
      month - an integer between 1 and 12 representing the month

    Returns:
      The number of days in the input month.
    """
    if month==12:
        return 31
    else:
        date1 = datetime.date(year, month, 1)
        date2 = datetime.date(year, month+1, 1)
        difference = date2 - date1
        return(difference.days) 
#print(days_in_month(2012,2))

def is_valid_date(year, month, day):
    """
    Inputs:
      year  - an integer representing the year
      month - an integer representing the month
      day   - an integer representing the day

    Returns:
      True if year-month-day is a valid date and
      False otherwise
    """
    if datetime.MINYEAR<=year<=datetime.MAXYEAR and 1<=month<=12 and 1<=day<= days_in_month(year, month):
        return True
    else:
        return False
#print(is_valid_date(2012,10,21))

def days_between(year1, month1, day1, year2, month2, day2):
    """
    Inputs:
      year1  - an integer representing the year of the first date
      month1 - an integer representing the month of the first date
      day1   - an integer representing the day of the first date
      year2  - an integer representing the year of the second date
      month2 - an integer representing the month of the second date
      day2   - an integer representing the day of the second date

    Returns:
      The number of days from the first date to the second date.
      Returns 0 if either date is invalid or the second date is
      before the first date.
    """
    date1=datetime.date(year1,month1,day1)
    date2=datetime.date(year2,month2,day2)
    if is_valid_date(year1,month1,day1) and is_valid_date(year2,month2,day2)and (date1<date2):
        difference=date2-date1
        #print(difference.days)
        return difference.days

    else:        
        return 0 


def age_in_days(year, month, day):
    """
    Inputs:
      year  - an integer representing the birthday year
      month - an integer representing the birthday month
      day   - an integer representing the birthday day

    Returns:
      The age of a person with the input birthday as of today.
      Returns 0 if the input date is invalid or if the input
      date is in the future.
    """
    todays_date=datetime.date.today()
    if is_valid_date(year, month,day) and (age_in_days<todays_date):
        return days_between(age_in_days(year,month,day),todays_date(year,month,day))
    else:
        return 0

Answer 1

这将返回2个日期之间的天数，特别是在出生日期和当前日期之间：

import datetime
birthday = datetime.date(1990,2,10) //datetime.date(YEAR,MONTH,DAY)
now = datetime.date.today()
delta = now - birthday
print delta.days

Answer 2

age_in_days是一个函数。不能与作为对象的todays_date进行比较。同样，在返回语句todays_date中不能这样传递。

def age_in_days(year,month,day):
    todays_date = dt.date.today()
    birthdate = dt.date(year,month,day)
    if is_valid(year,month,day) and (todays_date>birthdate):
        return days_in_between(todays_date.year,todays_date.month,todays_date.day,birthdate.year,birthdate.month,birthdate.day)
    else:
        return 0

用python计算天数

2 个答案: