Question

我最终创建了一个tableview，其中将填充一定数量的选项供用户点击。理想情况下，我希望用户单击一行，这将根据用户的选择在第二个控制器上显示图像。例如，＆＃34; photo1＆＃34; 会在控制器B上显示1张图片，而＆＃34;照片2＆＃34; 会在控制器上显示不同的图片B.我可以在现有的表视图代码中实现哪些代码发送到第二个控制器？

import UIKit

class adultcardiaclist: UITableViewController {

    let adultcardiac = ["photo1", "photo2", "photo3"]



    override func viewDidLoad() {
        super.viewDidLoad()


    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

    // MARK: - Table view data source

    override func numberOfSections(in tableView: UITableView) -> Int {
        return 1
    }

    override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return adultcardiac.count
    }

    override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
        let cell = tableView.dequeueReusableCell(withIdentifier: "transportCell", for: indexPath)

        cell.textLabel?.text = adultcardiac[indexPath.row]

        return cell
    } 
}

Answer 1

您可以使用TableView Conroller

中提供的默认代理

From java level I fixed this issue by chaning the time zone to America/New_York time

Long time = new Long(System.currentTimeMillis() );
        SimpleDateFormat sdf = new SimpleDateFormat();
        sdf.setTimeZone(TimeZone.getTimeZone("America/New_York"));
        Date date = new Date(sdf.format(new Date(time)));
        long utcDateInMilliSeconds = date.getTime();
        params.put("timestamp", new Long(utcDateInMilliSeconds/1000));

<强> - ＆GT;我的imageVC类

 import UIKit

class CustomTableController: UITableViewController {

    let adultcardiac = ["photo1", "photo2", "photo3"]

    override func viewDidLoad()
    {
        super.viewDidLoad()
    }

    // MARK: - Table view data source
    override func numberOfSections(in tableView: UITableView) -> Int {
        // #warning Incomplete implementation, return the number of sections
        return 1
    }

    override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        // #warning Incomplete implementation, return the number of rows
        return adultcardiac.count
    }


    override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
        let cell = tableView.dequeueReusableCell(withIdentifier: "transportCell", for: indexPath)

        cell.textLabel?.text = adultcardiac[indexPath.row]

        return cell
    }

    override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath)
    {
        let Vc = self.storyboard?.instantiateViewController(withIdentifier: "imageVC") as! imageVC

        switch indexPath.row
        {
        case 0:
            Vc.passedImage = UIImage.init(named: "screenShot")!
            self.navigationController?.pushViewController(Vc, animated: true)
            break;
        case 1:
            Vc.passedImage = UIImage.init(named: "screenShot1")!
            self.navigationController?.pushViewController(Vc, animated: true)
            break;
        case 2:
            Vc.passedImage = UIImage.init(named: "screenShot2")!
            self.navigationController?.pushViewController(Vc, animated: true)
            break;
        default:
            Vc.passedImage = UIImage.init(named: "screenShot")!
            self.navigationController?.pushViewController(Vc, animated: true)
        }
    }
}

<强> - ＆GT;输出

---＆GT;当TableView Controller加载到内存堆栈

时

- ＆GT;选择行时

- ＆GT;当DidSelect执行并显示结果时 - 新的ImageVc与传递的图像

<强> - ＆GT;我的故事板

Answer 2

在didSelectRowAt indexPath中，添加以下行

 self.performSegue(withIdentifier: "segue", sender: nil)

您应该在第二个viewcontroller中声明imageUrl变量

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {

            if segue.identifier == "segue" {

                if let indexPath = tableView.indexPathForSelectedRow {

                    let selectedRow = indexPath.row
                    let passingVal = segue.destination as! SecondViewController
                    passingVal.imageUrl = self.imageUrlArr[selectedRow] as? String
                }
         }
 }

Answer 3

在didSelectRowAt将所选索引图像传递给下一个viewController

func tableView(_ tableView: UITableView, didSelectRowAt
 indexPath: IndexPath){
    let controller = YourSecondVC(nibName:"YourSecondVC",bundle:nil)
    controller.selectedImageName = self.adultcardiac[indexPath.row]
   self.navigationController?.pushViewController(controller, animated: true)

}

在您的第二个ViewController中创建一个变量以接收第一个屏幕图像名称

var selectedImageName:String = ""

在你的secondViewController的viewWillAppear中将图片加载到imageView

self.YOUR_IMAGE_VIEW.image = UIImage(named:"\(selectedImageName:String)")

希望这会对你有所帮助

Answer 4

首先，确保您的第一个和第二个视图控制器之间存在segue（从表视图控制器1到详细信息视图屏幕）。确保segue具有名称。例如＆＃34; imageScreen＆＃34;

现在在你的第一个视图控制器的didSelectRowAtIndexPath事件中，像这样调用segue。

performSegueWithIdentifier("imageScreen", sender: nil)

现在，在第一个视图控制器的prepareForSegue方法中，您可以对其进行自定义以发送更多详细信息。

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) 
{       
   if(segue.identifier=="imageScreen")
   {
     let temp = segue.destinationViewController as! ViewControllerB
     temp.imageName = "Photo"
   }
}

假设您的详细信息屏幕的类名为ViewControllerB，它有一个名为imageName of String type的属性。您可以更新代码以使用真实的视图控制器。

Answer 5

使用didSelect委托方法像这样

如果从代码中删除

override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
       let selectedImage = adultcardiac[indexPath.row]
       let secondViewController = SecondViewController()
       secondViewController.image = selectedImage
       self.navigationController?.pushViewController(secondViewController, animated: true)
}

如果从storyBoard创建

override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
       let selectedImage = adultcardiac[indexPath.row]
       let storyBoard = UIStoryboard.init(name: "Main", bundle: nil)
       let secondViewController = storyBoard.instantiateViewController(withIdentifier: "secondViewController") as! secondViewController
       secondViewController.image = selectedImage
       self.navigationController?.pushViewController(secondViewController, animated: true)
}

TableView在新控制器上显示不同的图像

5 个答案: