如何以编程方式用用户友好的文本替换Spring的NumberFormatException?

时间:2018-02-06 18:59:47

标签: java spring replace message numberformatexception

我正在开发一个Spring Web应用程序,我有一个具有Integer属性的实体,用户可以在使用JSP表单创建新实体时填写该属性。此表单调用的控制器方法如下:

@RequestMapping(value = {"/newNursingUnit"}, method = RequestMethod.POST)
public String saveNursingUnit(@Valid NursingUnit nursingUnit, BindingResult result, ModelMap model) 
{
    boolean hasCustomErrors = validate(result, nursingUnit);
    if ((hasCustomErrors) || (result.hasErrors()))
    {
        List<Facility> facilities = facilityService.findAll();
        model.addAttribute("facilities", facilities);

        setPermissions(model);

        return "nursingUnitDataAccess";
    }

    nursingUnitService.save(nursingUnit);
    session.setAttribute("successMessage", "Successfully added nursing unit \"" + nursingUnit.getName() + "\"!");
    return "redirect:/nursingUnits/list";
}

validate方法只是检查数据库中是否已存在名称,因此我没有包含它。我的问题是,当我故意在现场输入文字时,我希望有一个很好的信息,例如“自动放电时间必须是一个数字!”。相反,Spring返回了这个绝对可怕的错误:

Failed to convert property value of type [java.lang.String] to required type [java.lang.Integer] for property autoDCTime; nested exception is java.lang.NumberFormatException: For input string: "sdf"

我完全理解为什么会发生这种情况,但我不能为我的生活弄清楚如何以编程方式用我自己的方式替换Spring的默认数字格式异常错误消息。我知道可以用于此类事情的消息源,但我真的想直接在代码中实现这一点。

修改

正如所建议的,我在我的控制器中构建了这个方法,但我仍然得到Spring的“未能转换属性值...”消息:

@ExceptionHandler({NumberFormatException.class})
private String numberError()
{
   return "The auto-discharge time must be a number!";
}

其他编辑

以下是我的实体类的代码:

@Entity
@Table(name="tblNursingUnit")
public class NursingUnit implements Serializable 
{
private Integer id;
private String name;
private Integer autoDCTime;
private Facility facility;

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
public Integer getId() 
{
    return id;
}

public void setId(Integer id) 
{
    this.id = id;
}

@Size(min = 1, max = 15, message = "Name must be between 1 and 15 characters long")
@Column(nullable = false, unique = true, length = 15)
public String getName() 
{
    return name;
}

public void setName(String name) 
{
    this.name = name;
}

@NotNull(message = "The auto-discharge time is required!")
@Column(nullable = false)
public Integer getAutoDCTime() 
{
    return autoDCTime;
}

public void setAutoDCTime(Integer autoDCTime) 
{
    this.autoDCTime = autoDCTime;
}

@ManyToOne (fetch=FetchType.EAGER)
@NotNull(message = "The facility is required")
@JoinColumn(name = "id_facility", nullable = false)
public Facility getFacility()
{
    return facility;
}

public void setFacility(Facility facility)
{
    this.facility = facility;
}

@Override
public boolean equals(Object obj) 
{
    if (obj instanceof NursingUnit)
    {
        NursingUnit nursingUnit = (NursingUnit)obj;
        if (Objects.equals(id, nursingUnit.getId()))
        {
            return true;
        }
    }
    return false;
}

@Override
public int hashCode() 
{
    int hash = 3;
    hash = 29 * hash + Objects.hashCode(this.id);
    hash = 29 * hash + Objects.hashCode(this.name);
    hash = 29 * hash + Objects.hashCode(this.autoDCTime);
    hash = 29 * hash + Objects.hashCode(this.facility);
    return hash;
}

@Override
public String toString()
{
    return name + " (" + facility.getCode() + ")";
}
}

再次编辑

我能够使用包含以下内容的类路径上的message.properties文件来完成这项工作:

typeMismatch.java.lang.Integer={0} must be a number!

配置文件中的以下bean声明:

@Bean
public ResourceBundleMessageSource messageSource() 
{
    ResourceBundleMessageSource resource = new ResourceBundleMessageSource();
    resource.setBasename("message");
    return resource;
}

这给了我正确的错误消息,而不是我可以使用的Spring泛型TypeMismatchException / NumberFormatException但是,我仍然希望尽可能以编程方式执行所有操作,并且我正在寻找替代方案。

感谢您的帮助!

4 个答案:

答案 0 :(得分:3)

您可以通过提供类似于此处所做的Spring DefaultBindingErrorProcessor的实现来覆盖该消息传递: Custom Binding Error Message with Collections of Beans in Spring MVC

答案 1 :(得分:2)

您可以使用以下方法注释方法:

@ExceptionHandler({NumberFormatException.class})
public String handleError(){
   //example
   return "Uncorrectly formatted number!";
}

并实现您想要做的任何事情,以防抛出该类型的异常。给定的代码将处理当前控制器中发生的异常。 如需进一步参考,请参阅this link

要进行全局错误处理,您可以通过以下方式使用@ControllerAdvice

@ControllerAdvice
public class ServiceExceptionHandler extends ResponseEntityExceptionHandler {

   @ExceptionHandler({NumberFormatException.class})
    public String handleError(){
       //example
       return "Uncorrectly formatted number!";
    }
} 

答案 2 :(得分:0)

@Martin,我问过您有关版本的信息,因为@ControllerAdvice从3.2版开始可用。

我建议您使用@ControllerAdvice,这是一个注释,可让您编写可在控制器之间共享的代码(用@Controller@RestController注释),但也可以仅适用于特定程序包或具体类中的控制器。

ControllerAdvice适用于@ExceptionHandler@InitBinder@ModelAttribute

您可以像这样@ControllerAdvice(assignableTypes = {YourController.class, ...})设置目标类。

@ControllerAdvice(assignableTypes = {YourController.class, YourOtherController.class})
public class YourExceptionHandler{
    //Example with default message
    @ExceptionHandler({NumberFormatException.class})
    private String numberError(){
        return "The auto-discharge time must be a number!";
    }

    //Example with exception handling
    @ExceptionHandler({WhateverException.class})
    private String whateverError(WhateverException exception){
        //do stuff with the exception
        return "Whatever exception message!";
    }

    @ExceptionHandler({ OtherException.class })
    protected String otherException(RuntimeException e, WebRequest request) {
        //do stuff with the exception and the webRequest
        return "Other exception message!";
    }
} 

需要记住的是,如果您没有设置目标,并且在不同的@ControllerAdvice类中为相同的异常定义了多个异常处理程序,Spring将应用它找到的第一个处理程序。如果同一@ControllerAdvice类中存在多个异常处理程序,则会引发错误。

答案 3 :(得分:-1)

处理 NumberFormatException。

@Override      
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenu.ContextMenuInfo menuInfo) {
    super.onCreateContextMenu(menu, v, menuInfo);
    LayoutInflater inflater = getLayoutInflater().from(this);
    View view = inflater.inflate(R.layout.custom_listview, null, false);
    menu.setHeaderView(view);
    menu.add("Delete");
    menu.add("Edit");
}

@Override
public boolean onContextItemSelected(MenuItem item) {
    AdapterView.AdapterContextMenuInfo info = (AdapterView.AdapterContextMenuInfo) item.getMenuInfo();
    int position = info.position;
    View v = listView.getChildAt(position);
    TextView typeTv = v.findViewById(R.id.custom_listview_type);
    TextView userTv = v.findViewById(R.id.custom_listview_user);
    TextView passTv = v.findViewById(R.id.custom_listview_password);

    if (item.getTitle().equals("Delete")) {
        db.execSQL("delete from user_added_accounts where accountType = '" + typeTv.getText().toString() + "' and username = '" + userTv.getText().toString() + "';");
        recreate();
    }

    if (item.getTitle().equals("Edit")) {
        update(typeTv.getText().toString(), userTv.getText().toString(), passTv.getText().toString());
    }

    return true;
}