Question

我正在实施一个Android应用程序，我想验证手机号码，但是我接替了我的代码：

 final String regexStr = "^(?:(?:\\+|0{0,2})91(\\s*[\\-]\\s*)?|[0]?)?[789]\\d{9}$";
final EditText chmobno = (EditText)login.findViewById(R.id.chmobno);
 mb=chmobno.getText().toString();

点击按钮

btnLogin.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {


            if( mb.matches(regexStr)){

                Toast.makeText(MainActivity.this,
                        "Login Sucessfull", Toast.LENGTH_LONG).show();
                login.cancel();
                Intent i=new Intent(MainActivity.this,TSO_Home.class);
                startActivity(i);
            }
            else{
                    Toast.makeText(MainActivity.this,
                            "Please enter Valid Mobile Number", Toast.LENGTH_LONG).show();
            }

当我输入有效号码时，它会转到其他部分..请帮我找错误

Answer 1

final String regexStr = "^(?:(?:\\+|0{0,2})91(\\s*[\\-]\\s*)?|[0]?)?[789]\\d{9}$";
final EditText chmobno = (EditText)login.findViewById(R.id.chmobno);
 mb=chmobno.getText().toString();
btnLogin.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {


            if( mb.matches(regexStr)){

                Toast.makeText(MainActivity.this,
                        "Login Sucessfull", Toast.LENGTH_LONG).show();
                login.cancel();
                Intent i=new Intent(MainActivity.this,TSO_Home.class);
                startActivity(i);
            }
            else{
                    Toast.makeText(MainActivity.this,
                            "Please enter Valid Mobile Number", Toast.LENGTH_LONG).show();
            }

印度手机的手机号码验证

1 个答案: