Question

我正在尝试在我的网站上实现通知功能。这是我的代码（希望我的方法是正确的）

- 创建一个名为notification的频道。{userId}（userId是经过身份验证的用户ID） - 例如，当我评论他的帖子时，触发通知广播的 NewComment 事件。{$ notification-＆gt; user_id}

这是我的代码：

public function newComment($post, $user){
    $notification = new Notification; // this is notification model for my database table
    $notification->type = 'new-comment';
    $notification->notified_by = $user->id;
    $notification->user_id = $post->owner->id;
    $notification->save();

    event(new NewNotification($notification));
}

NewNotification.php 事件

<?php

namespace App\Events;

use App\Models\Notification;
use App\Transformers\NotificationTransformer;
use Illuminate\Broadcasting\Channel;
use Illuminate\Broadcasting\InteractsWithSockets;
use Illuminate\Broadcasting\PresenceChannel;
use Illuminate\Broadcasting\PrivateChannel;
use Illuminate\Contracts\Broadcasting\ShouldBroadcast;
use Illuminate\Foundation\Events\Dispatchable;
use Illuminate\Queue\SerializesModels;

class NewNotification
{
    protected $notification;

    use Dispatchable, InteractsWithSockets, SerializesModels;

    /**
     * Create a new event instance.
     *
     * @return void
     */
    public function __construct(Notification $notification)
    {
        $this->notification = $notification;
    }

    /**
     * Get the channels the event should broadcast on.
     *
     * @return Channel|array
     */
    public function broadcastOn()
    {
        return new PresenceChannel('notification.' . $this->notification->user_id);
    }

    public function broadcastWith(){
        return fractal()->item($this->notification, new NotificationTransformer());
    }
}

广播频道路线：

Broadcast::channel('notification.{userId}', function($user, $userId){
      //comparing ($userId == $user->id) always turns true 
});

订阅客户端的状态通道（使用Vue）：

Echo.join('notification.' + this.user_id) //user_id is logged in user id
              .listen('NewNotification', function(response){
                console.log(response);
              });

由于某种原因，从未调用过事件。我不知道我是否应该改变广播频道路由中的逻辑。我应该通过通知ID并检查通知 - > user_id === $ user-＆gt; id。我已经通过这种方式进行了测试，但仍未在控制台中做出响应。

Answer 1

我希望有人觉得这个答案很有用：

为了发起一个事件，事件类应该实现 ShouldBroadcast 类。

所以

class NewNotification{
   //code here
}

成为

class NewNotification implements ShouldBroadcast{
   // code here
}

不要忘记运行队列：如果您尚未设置自动作业，请收听

Laravel向所有朋友广播通知

1 个答案: