Question

在oracle中，要删除所有表和约束，您可以键入类似

的内容

DROP TABLE myTable CASCADE CONSTRAINTS PURGE;

这将完全删除表及其依赖项。什么是SQL服务器等价？

Answer 1

在SQL Server Management Studio中，转到“选项/ SQL Server对象资源管理器/脚本”，然后启用“为从属对象生成脚本”。然后右键单击表格，脚本＆gt;下降到＆gt;新的查询窗口，它将为您生成。

Answer 2

我不相信SQL有一个同样优雅的解决方案。在删除表之前，必须首先删除任何相关约束。

幸运的是，这些都存储在信息架构中，您可以访问它以获取您的打击列表。

此博客文章应该能够为您提供所需内容： http://weblogs.asp.net/jgalloway/archive/2006/04/12/442616.aspx

-- t-sql scriptlet to drop all constraints on a table
DECLARE @database nvarchar(50)
DECLARE @table nvarchar(50)

set @database = 'DatabaseName'
set @table = 'TableName'

DECLARE @sql nvarchar(255)
WHILE EXISTS(select * from INFORMATION_SCHEMA.TABLE_CONSTRAINTS where constraint_catalog = @database and table_name = @table)
BEGIN
    select    @sql = 'ALTER TABLE ' + @table + ' DROP CONSTRAINT ' + CONSTRAINT_NAME 
    from    INFORMATION_SCHEMA.TABLE_CONSTRAINTS 
    where    constraint_catalog = @database and 
            table_name = @table
    exec    sp_executesql @sql
END

Answer 3

这可能是一个可怕的解决方案，但我发现它很快。它与Vinnie的答案类似，但SQL语句的产品是另一系列SQL语句，它们将删除所有约束和表。

(
select
  'ALTER TABLE ' + tc.table_name + ' DROP CONSTRAINT ' + tc.constraint_name + ';'
from
  INFORMATION_SCHEMA.TABLES t
  ,INFORMATION_SCHEMA.TABLE_CONSTRAINTS tc
where
  t.table_name = tc.table_name
  and tc.constraint_name not like '%_pk'
  and tc.constraint_name not like 'pk_%'
  and t.table_catalog='<schema>'
) UNION (
select
  'DROP TABLE ' + t.table_name + ';'
from
  INFORMATION_SCHEMA.TABLES t
where
  t.table_catalog='<schema>'
)

Answer 4

在一些桌子引用你的桌子之前，这一切都很有趣和游戏......

然后我必须改变提供的代码：

CREATE PROCEDURE _cascadeConstraints @database nvarchar(30) = NULL, @table nvarchar(60) = NULL
as
DECLARE @sql nvarchar(255)
WHILE EXISTS(select * from INFORMATION_SCHEMA.TABLE_CONSTRAINTS where constraint_catalog = @database and table_name = @table)
BEGIN
    select    @sql = 'ALTER TABLE ' + @table + ' DROP CONSTRAINT ' + CONSTRAINT_NAME 
    from    INFORMATION_SCHEMA.TABLE_CONSTRAINTS 
    where    constraint_catalog = @database and 
            table_name = @table
    select @sql = 'ALTER TABLE ' + tc.TABLE_NAME + ' DROP CONSTRAINT ' + tc.CONSTRAINT_NAME
      from INFORMATION_SCHEMA.TABLE_CONSTRAINTS tc join
                  INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS rc on
                   (rc.CONSTRAINT_CATALOG = tc.CONSTRAINT_CATALOG and
                    rc.CONSTRAINT_NAME = tc.CONSTRAINT_NAME) join
                  INFORMATION_SCHEMA.TABLE_CONSTRAINTS tc_pk on
                   (tc_pk.CONSTRAINT_CATALOG = rc.CONSTRAINT_CATALOG and
                    tc_pk.CONSTRAINT_NAME = rc.UNIQUE_CONSTRAINT_NAME)
     where tc.constraint_catalog = @database
       and tc_pk.TABLE_NAME = @table
    exec    sp_executesql @sql
END
go

Answer 5

最终我们正在删除我们的表格。所以我们可以简单地运行以下命令：

ALTER TABLE ... DROP CONSTRAINT ...

DROP TABLE ...

1＆GT; ALTER TABLE PRJ_DETAILS DROP CONSTRAINT FK_PRJ_TYPE ;

- 表名和Constraint Name是参数

2 - ; DROP TABLE。

第一个删除约束，其名称与其关联其次你可以放桌子。

它对我有用，也很容易。

Answer 6

我只需要删除外键

DECLARE @database nvarchar(50)
DECLARE @TABLE_NAME nvarchar(250)
DECLARE @CONSTRAINT_NAME nvarchar(250)
DECLARE @sql nvarchar(350)
set @database = 'XXX'


DECLARE db_cursor CURSOR FOR  
select TABLE_NAME, CONSTRAINT_NAME from INFORMATION_SCHEMA.TABLE_CONSTRAINTS where constraint_catalog = @database and CONSTRAINT_TYPE='FOREIGN KEY'

OPEN db_cursor  
FETCH NEXT FROM db_cursor INTO @TABLE_NAME, @CONSTRAINT_NAME  

WHILE @@FETCH_STATUS = 0  
BEGIN  

    select    @sql = 'ALTER TABLE ' + @TABLE_NAME + ' DROP CONSTRAINT ' + @CONSTRAINT_NAME 
    from    INFORMATION_SCHEMA.TABLE_CONSTRAINTS 
    where    constraint_catalog = @database and 
            table_name = @TABLE_NAME
    exec    sp_executesql @sql 

       FETCH NEXT FROM db_cursor INTO  @TABLE_NAME, @CONSTRAINT_NAME 
END  

CLOSE db_cursor  
DEALLOCATE db_cursor

SQL Server：drop table cascade等效？

6 个答案: