我创建了一个脚本,用于创建一个包含3列的易失性表,并插入5行:
create multiset volatile table dr (
period int
, st_date date
, end_date date
)
primary index (period) on commit preserve rows;
insert into dr (period,st_date,end_date)
select *
from( select *
from (select '201712' period
, '2017-10-01' st_date
, '2017-12-31' end_date
)t1
union all
select *
from (select '201612' period
, '2016-10-01' st_date
, '2016-12-31' end_date
)t2
union all
select *
from (select '201512' period
, '2015-10-01' st_date
, '2015-12-31' end_date
)t3
union all
select *
from (select '201412' period
, '2014-10-01' st_date
, '2014-12-31' end_date
)t4
union all
select *
from (select '201312' period
, '2013-10-01' st_date
, '2013-12-31' end_date
)t5
)t
我将把这个表加入到日期范围的其他几个表中。
这里我手动输入每个插入行的信息,这有点麻烦和低效。
是否有一种更自动化的方式来实现这一点,并让它完全脱离一个日期,例如2017-12-31?我可以自己解决逻辑问题,但不知道如何构造insert语句以允许这种逻辑。
谢谢!
修改 我希望能够连续3个月自动完成这项工作,也可以在跨越年份时自动化(例如2017-11-01至2018-01-31,或2017-12-01至2018-02-28),然后继续连续3个月回来5年。
答案 0 :(得分:2)
您可以使用sys_calendar.calendar
表来推导这些时段,使用某些窗口函数变得有点狡猾:
SELECT distinct
year_of_calendar * 100 + max(month_of_year) OVER (PARTITION BY year_of_calendar) as "period",
min(calendar_date) OVER (PARTITION BY year_of_calendar) as st_date,
max(calendar_date) OVER (PARTITION BY year_of_calendar) as end_date
FROM sys_calendar.calendar
WHERE month_of_year BETWEEN 10 AND 12
AND year_of_calendar BETWEEN 2013 AND 2017
+--------+------------+------------+
| period | st_date | end_date |
+--------+------------+------------+
| 201312 | 2013-10-01 | 2013-12-31 |
| 201412 | 2014-10-01 | 2014-12-31 |
| 201512 | 2015-10-01 | 2015-12-31 |
| 201612 | 2016-10-01 | 2016-12-31 |
| 201712 | 2017-10-01 | 2017-12-31 |
+--------+------------+------------+
将其包装到CREATE TABLE语句中:
CREATE MULTISET VOLATILE TABLE dr AS
(
SELECT distinct
year_of_calendar * 100 + max(month_of_year) OVER (PARTITION BY year_of_calendar) as "period",
min(calendar_date) OVER (PARTITION BY year_of_calendar) as st_date,
max(calendar_date) OVER (PARTITION BY year_of_calendar) as end_date
FROM sys_calendar.calendar
WHERE month_of_year BETWEEN 10 AND 12
AND year_of_calendar BETWEEN 2013 AND 2017
)
WITH DATA
PRIMARY INDEX ("period")
ON COMMIT PRESERVE ROWS;
答案 1 :(得分:2)
I would suggest using some logic based on TRUNC/ADD_MONTHS/LAST_DAY in a macro:
REPLACE MACRO testmac (in_date DATE)
AS
(
CREATE SET VOLATILE TABLE dr -- no need for MULTISET
AS
(
SELECT year_of_calendar * 100 + month_of_year AS PERIOD,
Add_Months(calendar_date,-2) AS st_date,
Last_Day(calendar_date) AS end_date
FROM sys_calendar.CALENDAR
WHERE year_of_calendar -- current_month and two previous months
BETWEEN Extract(YEAR From Add_Months(:in_date,-48))
AND Extract(YEAR From :in_date)
AND month_of_year = Extract(MONTH From :in_date)
AND day_of_month = 1 -- only one row per year
) WITH DATA
UNIQUE PRIMARY INDEX (PERIOD)
ON COMMIT PRESERVE ROWS;
);
EXEC testmac(DATE '2018-01-22');
You could also apply a recursive query or EXPAND ON.
Edit:
EXPAND ON is nice & short :-)
SELECT Extract(YEAR From End(pd)) * 100 + Extract(MONTH From End(pd)) AS PERIOD
,Trunc(Add_Months(End(pd),-2), 'mon') AS st_date
,Last_Day(End(pd)) AS end_date
FROM sys_calendar.CALENDAR -- specify the date once
WHERE calendar_date = DATE '2018-01-22' -- or :in_date in the macro
EXPAND ON PERIOD(Add_Months(calendar_date,-60), calendar_date) AS pd
BY INTERVAL '1' YEAR -- one row per year