Question

我正在使用Jaxrs，使用springboot 1.5.x创建Rest服务。我有一个带有Instant属性的bean。当我打电话给我的服务而不是

{
 "startTime": {
        "epochSecond": 1517243670,
        "nano": 986000000
     }
 }

我想获得一个iso格式的日期，即{"startTime":"2018-01-29T17:51:05"}

public class MyController{
 @GET
 @Path("/")
 public MyBean test();
  return new MyBean(Instant.now());  
}

public class MyBean{
 private Instant startTime;
}

我添加了java-8-time依赖项

    <dependency>
        <groupId>com.fasterxml.jackson.datatype</groupId>
        <artifactId>jackson-datatype-jsr310</artifactId>
        <version>2.9.3</version>
    </dependency>
    <dependency>
        <groupId>com.fasterxml.jackson.datatype</groupId>
        <artifactId>jackson-datatype-jdk8</artifactId>
        <version>2.8.0</version>
    </dependency>
    <dependency>
        <groupId>com.fasterxml.jackson.module</groupId>
        <artifactId>jackson-module-parameter-names</artifactId>
        <version>2.8.7</version>
    </dependency>

尝试了几种方法，但都没有效果。

@JsonFormat注释属性

@JsonFormat(shape=JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss") private Instant startTime;
ObjectMapper @Bean @Primary public ObjectMapper objectMapper(Jackson2ObjectMapperBuilder builder) { ObjectMapper objectMapper = builder.build(); objectMapper.registerModule(); objectMapper.configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false); return objectMapper; }

使用@Provider

public class ObjectMapperContextResolver implements 
ContextResolver<ObjectMapper>{
private final ObjectMapper MAPPER;

public ObjectMapperContextResolver() {
    MAPPER = new ObjectMapper();
    SimpleModule module = new SimpleModule();
    MAPPER.registerModule(new JSR310Module());
    MAPPER.registerModule(new JavaTimeModule());
    module.addSerializer(Instant.class, new DateSerializer());
    module.addDeserializer(Instant.class, new DateDeserializer());
    MAPPER.registerModule(module);

    MAPPER.configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false);
}
@Override
public ObjectMapper getContext(Class<?> type) {
    return MAPPER;
}

使用自定义序列化/去除化

@JsonDeserialize(using=DateDeserializer.class)
@JsonSerialize(using=DateSerializer.class)
private Instant startTime;

public class DateDeserializer extends JsonDeserializer<Instant>{
 @Override
 public Instant deserialize(JsonParser jp, DeserializationContext arg1)
    throws IOException, JsonProcessingException {
 return Instant.parse(jp.readValueAs(String.class));
 }
}

public class DateSerializer extends JsonSerializer<Instant> {
 @Override
 public void serialize(Instant value, JsonGenerator gen, 
 SerializerProvider sp) throws IOException {...}

我在这里显然遗漏了一些东西。

在springboot 1.5.3和jaxrs中格式化java.time.Instant bean属性

0 个答案: