Question

我已经在这里声明了所有变量。

    declare @FromDate as datetime;
    declare @ToDate as datetime;
    declare @OperID as varchar(20) = 'OP1';
    declare @Year as int = 2018
    declare @Month as int = 1

 set @FromDate = convert(date,convert(varchar,@Year) + '-' + 
    convert(varchar,@Month) + '-01')
    set @ToDate = dateadd(d,-1,DATEADD(m, 1, @FromDate))

这是查询的主体，我想输出Branch_No，operid是员工ID，Clock_date是时钟输入和时钟输出的日期，[I]代表时钟输入， [O]代表时钟输出。

    select Branch_no, operid, clock_date, [I], [O]
    from
    ( select Branch_no, operid, 
    convert(date, clock_date) as clock_date, 
    convert(time, clock_date) as clock_time, 
    clock_type, Workstation_no
    from ROSTER_TIMECLOCK
    where Clock_date >=CONVERT(DATETIME, @FromDate, 102)
    and Clock_date <=CONVERT(DATETIME, @ToDate, 102)
    and OperID=@OperID  ) as TheClock

然后，我使用Pivot组合查询以显示列中的数据，如此

分行编号|时钟日期|员工ID | IN | OUT

   PIVOT
  ( min(clock_time)
  FOR clock_type in ([I],[O])
  ) as ThePivot

The Table

Answer 1

创建一个临时表，其中包含所选时段的所有日期，然后在输出表上执行左连接，如下所示：

Create procedure nameofsp
@year int,
@month int
As

declare @FromDate as datetime
declare @ToDate datetime
declare @OperID varchar( 20 )  

set @FromDate = convert(datetime,convert(varchar,@Year) + '-' + 
    convert(varchar,@Month) + '-01')
    set @ToDate = dateadd(d,-1,DATEADD(m, 1, @FromDate))

--  create a table that contains all the dates for the period selected
declare @dates table( currentdate datetime )
;with cte( curr )
as
(
    select @fromdate
    union all
    select dateadd( d, 1, curr )
        from cte 
        where curr < @todate
)
insert into @dates( currentdate )
    select curr
        from cte

select a.CurrentDate, 
        b.operId, 
        b.Branch_No,
        b.I, 
        b.O 
    from @dates a 
    left outer join @inout b on b.clock_date = a.currentdate 
    order by a.currentdate, b.i

Answer 2

Create procedure procname
@year int,
@month int
As
(Rest of the code goes here)

删除年份和月份的声明。

关于这个SQL查询，如何根据用户对某个月份和年份的选择输出28/30/31天的列表

2 个答案: