有没有办法像这样发送HTTP POST:
1.在标题之前发送所有内容
做点什么......
3.发送请求的重置(数据)
我尝试使用HTTPUrlConnection。但是,我没有找到像send()这样的方法来首先显式发送部分HTTP请求 我是否必须自己去Socket建立请求?
添加更多说明:
也许问题不够明确。
所以,我们都知道HTTP是在套接字连接之上。
所以,我所说的并不是改变通过套接字发送数据的顺序。
但是,我需要套接字将所有数据发送到标头,然后保持,保持连接。将发送另一个http请求以触发服务器端的偶数。然后完成发送所有数据。关闭连接。
这与服务器端实现有关。但是,这不属于我的问题。所以,请不要说服务器不应该这样设计。
正如我已经说过的,这可以通过从socket构建HTTP请求来完成。但是,我想看看是否有任何方法可以实现这一点,而无需在套接字级别执行所有操作。
这可以在python中轻松完成。
self._conn = httplib.HTTPConnection(ip, port, timeout=120)
self._conn.putrequest('POST', '/yourserveraddresss')
self._conn.putheader('format', 'InterleavedInt16')
self._conn.putheader('number-of-channels', '2')
self._conn.putheader('sample-rate', '16000')
self._conn.putheader('transfer-encoding', 'chunked')
self._conn.endheaders()
因此,这将打开连接并发送标头。连接将保持开放。所以,你可以做点什么。然后:
self._conn.send(chunked_data)
self._conn.close()
所以,在Java中。如果您使用HttpUrlConnection。你能这样做吗? 或者,也许像Apache HttpClient这样的其他工具?
答案 0 :(得分:1)
不可能,您只能在请求的begening处发送标头,否则将被解释为消息的一部分。相关:https://www.w3.org/Protocols/rfc2616/rfc2616-sec5.html
HTTP 1.1基本上是连接上的文本,如果你想在服务器端口80中尝试打开套接字并通过管道发送文本,但你得到的只是ERRO 400无效请求。
修改:为了完善:
1-客户端在发送数据之前发送标头并等待一些事情:
package requestholder;
import java.io.BufferedReader;
import java.io.DataOutputStream;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;
import java.text.DateFormat;
import java.text.SimpleDateFormat;
public class RequestHolder {
private static final DateFormat dateFormater= new SimpleDateFormat("yyyy-mm-aa hh:MM:ss");
private static final String USER_AGENT = "Mozilla/5.0";
/**
* @param args the command line arguments
*/
public static void main(String[] args) throws Exception {
URL url = new URL("http://localhost:8084/WebApplication2/Hold");
HttpURLConnection httpConnection = (HttpURLConnection) url.openConnection();
//no buffer, imediate flush
httpConnection.setChunkedStreamingMode(1);
//just in case....might matter for some servers
httpConnection.setAllowUserInteraction(true);
// Send post request
httpConnection.setDoOutput(true);
//add request headers
httpConnection.setRequestMethod("POST");
httpConnection.setRequestProperty("User-Agent", USER_AGENT);
httpConnection.setRequestProperty("Accept-Language", "en-US,en;q=0.5");
StringBuilder someDataToSend = new StringBuilder();
for (int i = 0; i < 10; i++) {
someDataToSend.append("word_:");
someDataToSend.append(i);
someDataToSend.append(" ");
}
DataOutputStream outPutWriter = new DataOutputStream(httpConnection.getOutputStream());
//if ther's somenthing on the pipe (wich i doubt..), flush
outPutWriter.flush();
//************ represents slow logic here (Wait for other Thread/Connection), the headers has been sent and makes server wait for data
Thread.sleep(20000);
// send the remaing data
outPutWriter.writeBytes(someDataToSend.toString());
outPutWriter.flush();
outPutWriter.close();
//read the response from here
int responseCode = httpConnection.getResponseCode();
System.out.println("\nSending 'POST' request to URL : " + url);
System.out.println("Response Code : " + responseCode);
BufferedReader in = new BufferedReader(
new InputStreamReader(httpConnection.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
//print result
System.out.println(response.toString());
}
}
2-一个简单的servlet来证明这个概念:
package teste;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.PrintWriter;
import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.Enumeration;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
*/
@WebServlet(name = "Hold", urlPatterns = {"/Hold"})
public class Hold extends HttpServlet {
private static final DateFormat format= new SimpleDateFormat("yyyy-mm-dd HH:MM:ss");
/**
* Processes requests for both HTTP <code>GET</code> and <code>POST</code>
* methods.
*
* @param request servlet request
* @param response servlet response
* @throws ServletException if a servlet-specific error occurs
* @throws IOException if an I/O error occurs
*/
protected void processRequest(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
//print the headers
Enumeration<String> headerNames = request.getHeaderNames();
String header;
while (headerNames.hasMoreElements()) {
header = headerNames.nextElement();
System.out.println(format.format(System.currentTimeMillis())+":"+ header + ":" + request.getHeader(header));
}
BufferedReader dataReader = request.getReader();
/* low on porpuse, to generate more lines*/
char data[] = new char[1500];
while(dataReader.read(data)>-1){
System.out.println(format.format(System.currentTimeMillis())+":"+ new String(data));
}
//write a standart response
response.setContentType("text/html;charset=UTF-8");
try (PrintWriter out = response.getWriter()) {
/* TODO output your page here. You may use following sample code. */
out.println("<!DOCTYPE html>");
out.println("<html>");
out.println("<head>");
out.println("<title>Servlet Hold</title>");
out.println("</head>");
out.println("<body>");
out.println("<h1>Servlet Hold at " + request.getContextPath() + "</h1>");
out.println("</body>");
out.println("</html>");
}
}
// <editor-fold defaultstate="collapsed" desc="HttpServlet methods. Click on the + sign on the left to edit the code.">
/**
* Handles the HTTP <code>GET</code> method.
*
* @param request servlet request
* @param response servlet response
* @throws ServletException if a servlet-specific error occurs
* @throws IOException if an I/O error occurs
*/
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
processRequest(request, response);
}
/**
* Handles the HTTP <code>POST</code> method.
*
* @param request servlet request
* @param response servlet response
* @throws ServletException if a servlet-specific error occurs
* @throws IOException if an I/O error occurs
*/
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
processRequest(request, response);
}
/**
* Returns a short description of the servlet.
*
* @return a String containing servlet description
*/
@Override
public String getServletInfo() {
return "Short description";
}// </editor-fold>
}
3-客户端输出:
运行:
发送&#39; POST&#39;请求网址:http://localhost:8084/WebApplication2/Hold
回复代码:200
Servlet Hold
4-最后在servlet输出中,标题和数据之间有18秒(How accurate is Thread.sleep?):
2018-24-23 22:01:02:user-agent:Mozilla / 5.0
2018-24-23 22:01:02:accept-language:en-US,en; q = 0.5
2018-24-23 22:01:02:host:localhost:8084
2018-24-23 22:01:02:接受:text / html,image / gif,image / jpeg,*; q = .2, / ; Q = 0.2
2018-24-23 22:01:02:连接:保持活力
2018-24-23 22:01:02:content-type:application / x-www-form-urlencoded
2018-24-23 22:01:02:transfer-encoding:chunked
2018-24-23 22:01:18:word_:0 word_:1 word_:2 word_:3 word_:4 word_:5 word_:6 word_:7 word_:8 word_:9
现金:
https://www.mkyong.com/java/java-https-client-httpsurlconnection-example/
Implement pause/resume in file downloading
NetBeans模板。
答案 1 :(得分:0)
使用HttpUrlConnection看起来无法做到这一点,因为这种工具的高级封装和灵活性较低。
我最终使用socket从头开始构建HTTP。这样你就可以在流的任何一点暂停,然后再继续。
答案 2 :(得分:-1)
你的问题毫无意义。根据定义,标题首先出现,因此“标题之前的所有内容”都不会引用任何内容。
我找不到像
这样的方法"movies"
没有一个。除非您使用固定长度或分块传输模式,否则在您执行需要输入的操作(例如获取响应代码或输入流)之前,不会发送请求。
目前尚不清楚这里的实际目的是什么。服务器在收到整个请求之前不会做任何事情,如果你在发送请求时乱七八糟,它可能会让你抽出时间。
编辑现在看来您不知道send()
和URL
类,它们已经完成了您所需要的一切。我建议你查阅它们,并研究Java Tutorial的相关部分。