Question

我是c＃的新手所以它可能是一个愚蠢的问题，对不起：D

当我尝试使用方法Encrypt("c:\\test\testfile.txt", "testpwd")

时

它说：

参数“1”：不是从“string”到“System.IO.FileInfo”的转换可能的。

我不知道为什么它只能将其改为System.IO.FileInfo。当我使用随机密码（我有一个方法）时，它会说将System.Random转换为字符串是不可能的。谁能告诉我为什么？先感谢您。（抱歉我的英文）

using System;
using System.Windows.Forms;
using System.IO;
using System.Security.Cryptography;

namespace Project_Hermes
{
    static class Program
    {
        /* private static Random password = new Random();
         public static string RandomString(int length)
         {
             const string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
             return new string(Enumerable.Repeat(chars, length)
               .Select(s => s[password.Next(s.Length)]).ToArray());
         }*/

        [STAThread]
        static void Main()

        {
            string curFile = "c:\\oot26\\encrypd.txt";



            if (File.Exists(curFile))
            {
                Application.EnableVisualStyles();
                Application.SetCompatibleTextRenderingDefault(false);
                Application.Run(new Form1());

            } else
            {
                Encrypt(curFile, "password");

                //Console.WriteLine(password);

                Directory.CreateDirectory("C:\\oot26");

                File.Create(curFile);

                Application.EnableVisualStyles();
                Application.SetCompatibleTextRenderingDefault(false);
                Application.Run(new Form1());
            }
        }

        private const int SaltSize = 8;

        public static void Encrypt(FileInfo targetFile, string password)
        {
            var keyGenerator = new Rfc2898DeriveBytes(password, SaltSize);
            var rijndael = Rijndael.Create();
            rijndael.IV = keyGenerator.GetBytes(rijndael.BlockSize / 8);
            rijndael.Key = keyGenerator.GetBytes(rijndael.KeySize / 8);

            using (var fileStream = targetFile.Create())
            {
                fileStream.Write(keyGenerator.Salt, 0, SaltSize);

                using (var cryptoStream = new CryptoStream(fileStream, rijndael.CreateEncryptor(), CryptoStreamMode.Write))
                {
                }
            }
        }

        /*public static void Decrypt(FileInfo sourceFile, string password)
        {
            var fileStream = sourceFile.OpenRead();
            var salt = new byte[SaltSize];
            fileStream.Read(salt, 0, SaltSize);
            var keyGenerator = new Rfc2898DeriveBytes(password, salt);
            var rijndael = Rijndael.Create();
            rijndael.IV = keyGenerator.GetBytes(rijndael.BlockSize / 8);
            rijndael.Key = keyGenerator.GetBytes(rijndael.KeySize / 8);
            using (var cryptoStream = new CryptoStream(fileStream, rijndael.CreateDecryptor(), CryptoStreamMode.Read))
            {
            }*/
        }

    }
}

Answer 1

当<button id="foo">Click me</button>方法需要Encrypt对象时，您将string方法传递给FileInfo。试试这个：

Encrypt(new FileInfo(curFile), "password");

参数“1”：无法从“string”转换为“System.IO.FileInfo”

1 个答案: