Question

我实际上可以使用Maps插入数据，但我不能使用我自己的类中的对象。在火库文件中，他们说我可以。

错误是：

java.lang.RuntimeException: No properties to serialize found on class com.example.alumne.rateit.core.model.Restaurant

任何帮助都将不胜感激，谢谢。

class Restaurant(name: String, fiscName: String, cif: String, addr: String, city: String, phone: String, zipCode: String, country: String, email: String): Serializable{ }

override fun onClick(view: View?) {
    when(view?.id){
        btn_submit.id ->{
            if (checkForEmptyField()){
                val restName = et_rest_name.text.toString()
                val restFiscName = et_fiscal_name.text.toString()
                val restAddr = et_address.text.toString()
                val restPhone = et_phone.text.toString()
                val restZipCode = et_zip_code.text.toString()
                val restCif = et_cif.text.toString()
                val restCity = et_city.text.toString()
                val restCountry = et_country.text.toString()
                val restEmail = et_email.text.toString()

                /*val restaurant: HashMap<String, String> = HashMap()
                restaurant.put("name",restName)
                restaurant.put("fiscName",restFiscName)
                restaurant.put("address",restAddr)
                restaurant.put("phone",restPhone)
                restaurant.put("zipCode",restZipCode)
                restaurant.put("cif",restCif)
                restaurant.put("city",restCity)
                restaurant.put("country",restCountry)
                restaurant.put("email",restEmail)*/

                val rest = Restaurant(restName,restFiscName,restCif,restAddr,restCity,restPhone,restZipCode,restCountry,restEmail)
                if (bd.collection("restaurants").document().set(rest).isSuccessful){
                    Utilities.showMessage(view,"Restaurant added correctly")
                }else{
                    Utilities.showMessage(view,"Error adding restaurant")
                }
            }else{
                if (view != null) {
                    Utilities.showMessage(view,"Fill all fields")
                }
            }
        }
    }
}

Answer 1

正如here

所解释的那样

每个自定义类必须具有不带参数的公共构造函数。此外，该类必须包含每个属性的公共getter。

Answer 2

Firebase不接受set方法的对象。您可以简单地使用接口，或将类对象转换为接口，如下所示。创建一个这样的接口和类。

export interface IUser {
  name: string;
  email: string;
  id: string;
}
export class User implements IUser {
  name: string;
  email: string;
  id: string;
  constructor(args) {
    this.name = args.name;
    this.email = args.email;
    this.id = args.id;
  }
}

然后，您可以使用以下方式将对象转换为接口实例

var userData = new User({
    name: "user",
    email: "user@gmail.com",
    id: ":LKJDFasdfFSDsadfhAdfsf76dfasdf",
});

var user: IUser = <IUser>JSON.parse(JSON.stringify(userData));

您可以在set方法中使用此User模型。

this.firestore.collection('users').doc(this.userData.id).set(user);

有关更多信息，请访问Firestore官方文档： https://firebase.google.com/docs/firestore/manage-data/add-data

为什么我不能将对象插入到firebase.firestore Android Studio中？

2 个答案: