我有以下类用于幻灯片放映图像使用sliderAdapter构造函数并传递一个字符串列表并且其工作正常。
public class sliderAdapter extends PagerAdapter {
private Context context;
private List<String> URLs = new ArrayList<>();
sliderAdapter(Context context, List<String> URLs){
this.URLs = URLs;
this.context = context;
}
@Override
public int getCount() {
return URLs.size();
}
@Override
public boolean isViewFromObject(View view, Object object) {
return (view== object);
}
@Override
public Object instantiateItem(ViewGroup container, int position) {
LayoutInflater layoutInflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View view = layoutInflater.inflate(R.layout.slideshow_layout,container,false);
ImageView img = view.findViewById(R.id.imageview);
Glide.with(context).load(URLs.get(position)).into(img);
container.addView(view);
return view;
}
@Override
public void destroyItem(ViewGroup container, int position, Object object) {
container.removeView((LinearLayout)object);
}
}
现在我需要通过添加从drawable文件夹加载图像的功能来改进我的滑块,所以我必须传递整数列表,我不知道确切的方法做到这一点
据我所知,我应该创建接受整数列表的新构造函数 但是除了所有其他函数之外,我应该如何改变我的类以适应两个构造函数?
任何想法都将不胜感激
答案 0 :(得分:2)
您可以这样做:
public class Item{
String url;
int id;
boolean link = false;
boolean resource = false;
public Item(int id){
this.id = id;
resource = true;
}
public Item(String url){
this.url = url;
link = true;
}
public boolean isLink(){
return link;
}
public boolean isResource(){
return resource;
}
public int getId(){
return id;
}
public String getUrl(){
return url;
}
}
public class sliderAdapter extends PagerAdapter {
private Context context;
private List<Item> items = new ArrayList<>();
sliderAdapter(Context context, List<Item> items){
this.items = items;
this.context = context;
}
@Override
public int getCount() {
return items.size();
}
@Override
public boolean isViewFromObject(View view, Object object) {
return (view== object);
}
@Override
public Object instantiateItem(ViewGroup container, int position) {
LayoutInflater layoutInflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View view = layoutInflater.inflate(R.layout.slideshow_layout,container,false);
ImageView img = view.findViewById(R.id.imageview);
Item item = items.get(position);
if(item.isLink()){
Glide.with(context).load(item.getUrl()).into(img);
}else{
img.setImageResource(item.getId());
}
container.addView(view);
return view;
}
@Override
public void destroyItem(ViewGroup container, int position, Object object) {
container.removeView((LinearLayout)object);
}
}
在此示例中,我没有将两个不同的列表传递给适配器(List<String>
或List<Integer>
),而是将其更改为接受Item
个对象的列表。如您所见,Item
对象可以包含URL或可绘制资源ID。在适配器中,我检查每个项目以查看它是什么类型的项目,以便我可以使用适当的方法来设置ImageView
的图像。