我刚刚在我的laravel应用程序中实现了一个lat。当我在地图上添加地址时,它建议一个地址,当我选择addressit返回lat-long。我只想在地图上鼠标位置上的那个lat。那怎么能这样呢。添加了所有正在选择地址的代码。
这是我的观看代码
<div class="form-group">
<label class="col-sm-2 control-label"></label>
<div class="col-md-6">
<h3 class="text-center"></h3>
<input id="searchInput" class="form-control" type="text" placeholder="Enter a location">
<div class="google-map" id="map"></div>
</div>
</div>
<div class="form-group"><label class="col-sm-2 control-label">Latitude </label>
<div class="col-sm-6">
<input type="text" readonly name="latitude" id="latitude" @if(isset($activity)) value="{{ $activity->latitude }}" @else value="{{ old('latitude') }}" @endif class="form-control">
@if ($errors->has('latitude'))
<div class="text-left" style="color:red;">
<strong>Alert !</strong> {{ $errors->first('latitude') }}
</div>
@endif
</div>
</div>
<div class="form-group"><label class="col-sm-2 control-label">Longitude </label>
<div class="col-sm-6">
<input type="text" readonly name="longitude" id="longitude" @if(isset($activity)) value="{{ $activity->longitude }}" @else value="{{ old('longitude') }}" @endif class="form-control">
@if ($errors->has('longitude'))
<div class="text-left" style="color:red;">
<strong>Alert !</strong> {{ $errors->first('longitude') }}
</div>
@endif
</div>
</div>
这是地图脚本:
<script>
function initMap() {
var map = new google.maps.Map(document.getElementById('map'), {
center:new google.maps.LatLng(20.593684,78.96288000000004),
zoom: 4
});
var input = document.getElementById('searchInput');
map.controls[google.maps.ControlPosition.TOP_LEFT].push(input);
var autocomplete = new google.maps.places.Autocomplete(input);
autocomplete.bindTo('bounds', map);
var infowindow = new google.maps.InfoWindow();
var marker = new google.maps.Marker({
map: map,
anchorPoint: new google.maps.Point(0, -29)
});
autocomplete.addListener('place_changed', function() {
infowindow.close();
marker.setVisible(false);
var place = autocomplete.getPlace();
if (!place.geometry) {
window.alert("Autocomplete's returned place contains no geometry");
return;
}
// If the place has a geometry, then present it on a map.
if (place.geometry.viewport) {
map.fitBounds(place.geometry.viewport);
} else {
map.setCenter(place.geometry.location);
map.setZoom(17);
}
marker.setIcon(({
url: place.icon,
size: new google.maps.Size(71, 71),
origin: new google.maps.Point(0, 0),
anchor: new google.maps.Point(17, 34),
scaledSize: new google.maps.Size(35, 35)
}));
marker.setPosition(place.geometry.location);
marker.setVisible(true);
var address = '';
if (place.address_components) {
address = [
(place.address_components[0] && place.address_components[0].short_name || ''),
(place.address_components[1] && place.address_components[1].short_name || ''),
(place.address_components[2] && place.address_components[2].short_name || '')
].join(' ');
}
/* infowindow.setContent('<div><strong>' + place.name + '</strong><br>' + address);
infowindow.open(map, marker);*/
//document.getElementById('addressTwo').value = place.formatted_address;
document.getElementById('latitude').value = place.geometry.location.lat();
document.getElementById('longitude').value = place.geometry.location.lng();
}); } </script>
查看屏幕:
我该怎么做?
答案 0 :(得分:0)
有几种方法,您首先需要访问地图项目,无论是地图对象还是叠加层。
对于地图对象,请使用:
map.getProjection().fromPointToLatLng(new google.maps.Point(x, y))
从叠加层中您将使用:
overlay.getProjection().fromContainerPixelToLatLng(new google.maps.Point(x, y));
或者,您可以在mousedown上添加一个事件监听器来捕获指针位置并提取latlng:
google.maps.event.addListener(map, 'mousemove', function (event) {
// do something with event.latLng
});