Question

HY，我会将json发送到网关

我可以使用以下代码执行登录网关：

private static final String SPN_IP = "192.168.0.2";
        private static final String SPN_LOGIN = "myadmin";
        private static final String SPN_PASSWORD = "mypasswor";
        private static String jsonSicuro = "[\"txmsgid\":,\"trycount\": 5,\"port\": 2,\"payload\": \"01\",\"ack\": true,\"mote\": \"17A7F79\"  }]";


        public static void main(String[] args) throws IOException, KeyStoreException, NoSuchAlgorithmException, KeyManagementException, AuthenticationException, URISyntaxException {
            // SSL management
            SSLContextBuilder builder = new SSLContextBuilder();
            builder.loadTrustMaterial(null, new TrustSelfSignedStrategy()); // trust self-signed cert
            SSLConnectionSocketFactory sslSocketFactory = new SSLConnectionSocketFactory(builder.build(), new HostnameVerifier() {
                @Override
                public boolean verify(String hostname, SSLSession sslSession) {
                    return SPN_IP.equals(hostname); // validate the host name
                }
            });

            // Create client
            CloseableHttpClient httpclient = HttpClientBuilder.create()
                    .setSSLSocketFactory(sslSocketFactory)
                    .build();

            // Create HTTP GET request
            HttpGet httpGet = new HttpGet("https://" + SPN_IP);

            // HTTP digest
            DigestScheme digestAuth = new DigestScheme();
            digestAuth.overrideParamter("algorithm", "MD5");
            digestAuth.overrideParamter("realm", "https://" + SPN_IP);
            digestAuth.overrideParamter("nonce", Long.toString(new Random().nextLong(), 36));
            digestAuth.overrideParamter("qop", "auth");
            digestAuth.overrideParamter("nc", "0");
            digestAuth.overrideParamter("cnonce", DigestScheme.createCnonce());

            // Send HTTP digest header
            Header auth = (Header) digestAuth.authenticate(new UsernamePasswordCredentials(SPN_LOGIN, SPN_PASSWORD), httpGet, null);
            System.out.println(((org.apache.http.Header) auth).getName());
            System.out.println(((org.apache.http.Header) auth).getValue());
            httpGet.setHeader((org.apache.http.Header) auth);
            ResponseHandler<String> responseHandler = new BasicResponseHandler();
            System.out.println("Executing request: " + httpGet.getRequestLine());
            String response = httpclient.execute(httpGet, responseHandler);
            System.out.println("Response: " + response);

网关响应“授权确定”..................... 现在，我该如何发送json？我尝试“httpGet.setParams（（HttpParams）（（HttpEntity）new StringEntity（jsonSicuro）））;”但我有错误

Answer 1

我们无法将json发送到httpGet，您只能将请求正文发送到httpPost。请检查 What is the difference between POST and GET?

另请查看以下链接以传递参数 commons httpclient - Adding query string parameters to GET/POST request

将json httpGet连接插入java

1 个答案: