Question

我有一堆地址：

123 Main Street, PO Box 345, Chicago, IL 92921
1992 Super Way, Bakersfield, CA
234 Wonderland Lane, Attn: Daffy Duck, Orlando, FL 09922

当我对每个字符串myStr.split(',')时，我怎么能在那里剪掉第二个字符串？

我的想法是想要回归：

123 Main Street, Chicago, IL 92921
1992 Super Way, CA
234 Wonderland Lane, Orlando, FL 09922

我可以遍历每个部分，并构建另一个字符串，跳过第二个索引，但是想知道是否有更好的方法。

我现在拥有的：

def filter_address(address):
    print("Filtering address on",address)
    updated_addr = ""
    indx = 0
    for section in address.split(","):
        if indx != 1:
            updated_addr = updated_addr + "," + section
        indx += 1
    updated_addr = updated_addr[1:]  # This is to remove the leading `,`

new_address = filter_address("123 Main Street, Chicago, IL 92921")

Answer 1

你可以在python中使用del并在分割后用“，”将字符串的组件粘合回来。

例如：

address = "123 Main Street, PO Box 345, Chicago, IL 92921".split(",")
del address[1]
pretty_address = ", ".join(address)

print(pretty_address) # Gives 123 Main Street,  Chicago,  IL 92921

在逗号分隔的字符串中，保留除第二部分之外的所有字符串

1 个答案: