我使用以下方法将列表转换为XML。如何更改此设置以将嵌套列表转换为XML。
private string ConvertProductListToXML(List<ProductDM> productDMList)
{
var xEle = new XElement("Products",
from emp in productDMList
select new XElement("Product",
new XElement("ProductID", emp.ProductID),
new XElement("Cost", emp.Cost),
new XElement("UPC", emp.UPC),
new XElement("TaxStatus", emp.TaxStatus)
));
return ConvertToInnerXML(xEle);
}
public static string ConvertToInnerXML(XElement el)
{
var reader = el.CreateReader();
reader.MoveToContent();
return reader.ReadInnerXml();
}
模型
public class ProductDM
{
public int? ProductID { get; set; }
public string UPC { get; set; }
public string TaxStatus { get; set; }
public Decimal Cost { get; set; }
}
如果数据模型如下所示,如何使用扩展列表,我该如何修改上述代码。
public class ProductDM
{
public int? ProductID { get; set; }
public string UPC { get; set; }
public string TaxStatus { get; set; }
public Decimal Cost { get; set; }
public List<InventoryDM> CabinetList { get; set; }
}
public class InventoryDM
{
public int InventoryID { get; set; }
}
预期产出:
<Product><ProductID>40</ProductID><Cost>2</Cost><UPC>3121</UPC>
<TaxStatus>NO</TaxStatus><CabinetList>
<InventoryID>1</InventoryID></CabinetList><CabinetList>
<InventoryID>2</InventoryID></CabinetList></Product>
答案 0 :(得分:2)
我不会使用xElement。 最简单的解决方案是使用xml序列化。 你的课应该像这样更新
using System;
using System.Xml.Serialization;
using System.Collections.Generic;
namespace YourAppNameSpace
{
[XmlRoot(ElementName="CabinetList")]
public class InventoryDM {
[XmlElement(ElementName="InventoryID")]
public string InventoryID { get; set; }
}
[XmlRoot(ElementName="Product")]
public class Product {
[XmlElement(ElementName="ProductID")]
public int? ProductID { get; set; }
[XmlElement(ElementName="Cost")]
public Decimal Cost { get; set; }
[XmlElement(ElementName="UPC")]
public string UPC { get; set; }
[XmlElement(ElementName="TaxStatus")]
public string TaxStatus { get; set; }
[XmlElement(ElementName="CabinetList")]
public List<InventoryDM> CabinetList { get; set; }
}
}
将类序列化为xml
public static string SerializeObject(object obj)
{
System.Xml.XmlDocument xmlDoc = new System.Xml.XmlDocument();
System.Xml.Serialization.XmlSerializer serializer = new System.Xml.Serialization.XmlSerializer(obj.GetType());
using (System.IO.MemoryStream ms = new System.IO.MemoryStream())
{
serializer.Serialize(ms, obj);
ms.Position = 0;
xmlDoc.Load(ms);
return xmlDoc.InnerXml;
}
}