Question

我有一个拼写字符串的问题我尝试在游乐场中编写一个函数并测试它的运行时间我不知道是否有更好的拼接字符串功能。
有什么想法建议我吗？感谢。

func spliteMessage() -> String {

let startTime = CACurrentMediaTime()
print("--> StartTime: \(startTime)")

let str:String = "<a href=\"url://app/user/5a4defba4d092f3f00e0fdb1\">@user1 </a><a href=\"url://app/user/5a4defba4d092f3f00e0fdb2\">@user2 </a><a href=\"url://app/user/5a4defba4d092f3f00e0fdb3\">@user3 </a><a href=\"url://app/user/5a4defba4d092f3f00e0fdb4\">@user4 </a><a href=\"url://app/user/5a4defba4d092f3f00e0fdb5\">@user5 </a><a href=\"url://app/user/5a4defba4d092f3f00e0fdb6\">@user6 </a><a href=\"url://app/user/5a4defba4d092f3f00e0fdb7\">@user7 </a><a href=\"url://app/user/5a4defba4d092f3f00e0fdb8\">@user8 </a><a href=\"url://app/user/5a4defba4d092f3f00e0fdb9\">@user9 </a><a href=\"url://app/user/5a4defba4d092f3f00e0fd10\">@user10 </a><a href=\"url://app/user/5a4defba4d092f3f00e0fd11\">@user11 </a><a href=\"url://app/user/5a4defba4d092f3f00e0fd12\">@user12 </a> Have a nice day!"

let fullArr = str.components(separatedBy: "</a>")
var finalArray = [[String:String]]()
var commonMessage:String = ""
var taggedMessage:String = ""

fullArr.forEach { (string) in

    if string.hasPrefix("<a href=\"url://app/user/") {

        var a = string.replacingOccurrences(of: "<a href=\"url://app/user/", with: "")
        var userId = (a as NSString).substring(to: 24)
        var name = (a as NSString).substring(from: 26)

        finalArray.append([userId:name])

    }else{

        commonMessage = string
    }
}

finalArray.forEach { (dic) in
    dic.forEach({ (id,name) in
        taggedMessage += name
    })
}

let finalmsg = taggedMessage + commonMessage

print("--> finalmsg: \(finalmsg)")

let endTime = CACurrentMediaTime()
print("--> EndTime: \(endTime)")

print("--> Time: \(endTime - startTime)")

return finalmsg
}

最终印刷品：

- ＆GT; StartTime：22153.978737749
   - ＆GT; finalmsg：@ user1 @ user2 @ user3 @ user4 @ user5 @ user6 @ user7 @ user8 @ user9 @ user10 @ user11 @ user12祝你有愉快的一天！
   - ＆GT;结束时间：22154.030463062
   - ＆GT;时间：0.0517253129983146

更新：

//change finalArray type to dictionary.
finalArray = [String:String]()

finalArray.forEach({ (id,name) in
    taggedMessage += name
}

如何快速拆分String以获得Swift的最终结果

0 个答案: