我想创建一个我在企业云中拥有的所有文件和文件夹的索引，这样我就可以对其进行备份并将索引存储到txt文件中，之后我将比较最后两个备份（ txt文件）检查哪些文件/文件夹更改了名称。
我已经尝试过这段代码，但它仅限于插入代码的for循环次数，我想知道我是否可以以几乎无限的方式进行，因为我从来不知道是否有人会添加文件夹到任何子文件夹：
for f in next(os.walk(path))[1]:
folder=('{}' + ". " + f).format(a)
print(folder,file=open(filename, "a"))
path1=path+f
for f in next(os.walk(path1))[2]:
files = (" " + f)
print(files,file=open(filename, "a"))
b=1
for f in next(os.walk(path1))[1]:
folder=(" " + '{}' + "." + '{}' + ". " + f).format(a,b)
print(folder,file=open(filename, "a"))
path2=path1+("\\")+f
for f in next(os.walk(path2))[2]:
files = (" " + f)
print(files,file=open(filename, "a"))
c=1
for f in next(os.walk(path2))[1]:
folder=(" " + '{}' + "." + '{}' + "." + '{}' + ". " + f).format(a,b,c)
print(folder,file=open(filename, "a"))
path3=path2+("\\")+f
for f in next(os.walk(path3))[2]:
files = (" " + f)
print(files,file=open(filename, "a"))
d=1
for f in next(os.walk(path3))[1]:
folder=(" " + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + ". " + f).format(a,b,c,d)
print(folder,file=open(filename, "a"))
path4=path3+("\\")+f
for f in next(os.walk(path4))[2]:
files = (" " + f)
print(files,file=open(filename, "a"))
e=1
for f in next(os.walk(path4))[1]:
folder=(" " + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + ". " + f).format(a,b,c,d,e)
print(folder,file=open(filename, "a"))
path5=path4+("\\")+f
for f in next(os.walk(path5))[2]:
files = (" " + f)
print(files,file=open(filename, "a"))
g=1
for f in next(os.walk(path5))[1]:
folder=(" " + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + ". " + f).format(a,b,c,d,e,g)
print(folder,file=open(filename, "a"))
path6=path5+("\\")+f
for f in next(os.walk(path6))[2]:
files = (" " + f)
print(files,file=open(filename, "a"))
h=1
for f in next(os.walk(path6))[1]:
folder=(" " + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + ". " + f).format(a,b,c,d,e,g,h)
print(folder,file=open(filename, "a"))
path7=path6+("\\")+f
for f in next(os.walk(path7))[2]:
files = (" " + f)
print(files,file=open(filename, "a"))
i=1
for f in next(os.walk(path7))[1]:
folder=(" " + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + ". " + f).format(a,b,c,d,e,g,h,i)
print(folder,file=open(filename, "a"))
path8=path7+("\\")+f
for f in next(os.walk(path8))[2]:
files = (" " + f)
print(files,file=open(filename, "a"))
for f in next(os.walk(path8))[1]:
folder=(" " + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + ". " + f).format(a,b,c,d,e,g,h,i,j)
print(folder,file=open(filename, "a"))
path9=path8+("\\")+f
for f in next(os.walk(path9))[2]:
files = (" " + f)
print(files,file=open(filename, "a"))
k=1
for f in next(os.walk(path9))[1]:
folder=(" " + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + "." + '{}' + ". " + f).format(a,b,c,d,e,g,h,i,j,k)
print(folder,file=open(filename, "a"))
path10=path9+("\\")+f
for f in next(os.walk(path10))[2]:
files = (" " + f)
print(files,file=open(filename, "a"))
k=k+1
j=j+1
i=i+1
h=h+1
g=g+1
e=e+1
d=d+1
c=c+1
b=b+1
a=a+1
有可能做我想做的事吗？
在代码的开头，我要求它询问云的主文件夹在哪里（在Windows上），因为我们都使用OneDrive应用程序在计算机中安装云。
这是我想要展示的方式的一个例子：
2. Handover
2.1. 2018
2.1.1. 1_January
RE 0112018 Report A (by PC).msg
RE 0112018 Report M (by FM).msg
RE 0112018 Report N (by RB).msg
有另一个想法，如果我用值创建一个数组怎么办？例如：
[main_folder，子文件夹，子文件夹，...]
所以这样我会对主文件夹中的所有值执行for循环，抛出子文件夹的所有值等等...
然后关联“1”到数组的第一个值，即“1.1”。到第二个等等
这是一件简单易事的事吗？并检查它是否有子文件夹，是否必须添加数组值？
答案 0 :(得分：0)
几乎可以肯定，已有一种工具可以像你想要的那样索引文件。
那就是说，如果你想自己做，你可能需要这样的recursive function（伪代码）：
def get_files(path, indent):
for f in children_in_path:
# print appropriately, e.g. print('{} {}'.format(indent*' ', f)
next_path = path+f
get_files(next_path, indent+2)
也许您还需要通过将标题作为参数添加到标题中来跟踪标题。
答案 1 :(得分：0)
这是一种可能的解决方案
from pathlib import Path
def iter_subtree(path, layer=0):
"""Recursively iterate over each item in path
and print item's name.
"""
# make Path object from input string
path = Path(path)
# iter the directory
for p in path.iterdir():
if p.is_file():
print('\t'*layer, p.name)
elif p.is_dir():
print('\t'*layer, p.name+'/')
iter_subtree(p, layer+1)
else:
raise FileNotFoundError()