Question

表用户

a = data.frame(x = c(1,2), y = 1:2)
b = data.frame(x = c(3,4), y = 1:2)

frameList = list(a = a, b = b)

lapply(1:length(names(frameList)), function(x) {

       names(frameList[[x]]) <- paste(names(frameList)[x], names(frameList[[x]]), sep = "_")

       return(frameList[[x]])

})

[[1]]
  a_x a_y
1   1   1
2   2   2

[[2]]
  b_x b_y
1   3   1
2   4   2

表翻译

+-----+-------+----------+------------+
| id  |  name |  gender  |   computer |
+-----+-------+----------+------------+
| 1   |  ben  |     1    |       3    |
+-----+-------+----------+------------+

最终结果

+-----+--------+
| id  |  trans |
+-----+--------+
| 1   |   boy  |
| 2   |   girl |
| 3   |   pc   |
| 4   |   mac  |
+-----+--------+

我有2个表，一个是用户数据，另一个是翻译。

我想使用翻译表来翻译用户的性别＆amp;计算机的价值观有谁知道如何实现这个目标？

Answer 1

使用 JOIN 。

<强>查询

 select 
   t1.`id`,
   t1.`name`,
   t2.`trans` as `gender`,
   t3.`trans` as `computer`
from `user` t1
join `translate` t2
on t1.`gender` = t2.`id`
join `translate` t3
on t1.`computer` = t3.`id`;

Answer 2

你提出这个问题的方式，它似乎不是一个翻译问题（在语言意义上），而是一个标准的数据库分区问题。更标准的解决方案是在各自的表中定义您的实体：

用户

+-----+--------+------------+--------------+ | id | name | genderId | computerId | +-----+--------+------------+--------------+ | 1 | ben | 1 | 1 | +-----+--------+------------+--------------+

<强>性别

+-----+--------+ | id | name | +-----+--------+ | 1 | boy | +-----+--------+ | 2 | girl | +-----+--------+

<强>计算机

+-----+--------+ | id | name | +-----+--------+ | 1 | pc | +-----+--------+ | 2 | mac | +-----+--------+

...然后您的查询显示为：

SELECT * FROM user INNER JOIN gender ON user.genderId = gender.id INNER JOIN computer ON user.computerId = computer.id

Mysql使用另一个表来翻译值

2 个答案: