我有以下数组输出
Array
(
[0] => Array
(
[id] => 1
[bus_id] => 1
[stop_order_id] => 14
[bus_time] => 09:59:00
[bus_direction] => 1
[trip] => 1
[created_at] => -0001-11-30 00:00:00
[updated_at] => -0001-11-30 00:00:00
[route_id] => 1
[stop_id] => 8
[stop_orders] => 14
[route_name] => Sydney
[seo_url] => sydney
[stop_name] => stop_8
[bus_name] => M.S
[bus_number] =>
[bus_image] =>
[bus_stop_start] =>
[bus_stop_end] =>
)
[1] => Array
(
[id] => 1
[bus_id] => 1
[stop_order_id] => 22
[bus_time] => 10:50:00
[bus_direction] => 1
[trip] => 1
[created_at] => -0001-11-30 00:00:00
[updated_at] => -0001-11-30 00:00:00
[route_id] => 1
[stop_id] => 18
[stop_orders] => 22
[route_name] => Sydney
[seo_url] => sydney
[stop_name] => stop_18
[bus_name] => M.S
[bus_number] =>
[bus_image] =>
[bus_stop_start] =>
[bus_stop_end] =>
)
[2] => Array
(
[id] => 1
[bus_id] => 1
[stop_order_id] => 22
[bus_time] => 10:55:00
[bus_direction] => 2
[trip] => 1
[created_at] => -0001-11-30 00:00:00
[updated_at] => -0001-11-30 00:00:00
[route_id] => 1
[stop_id] => 18
[stop_orders] => 22
[route_name] => Sydney
[seo_url] => sydney
[stop_name] => stop_18
[bus_name] => M.S
[bus_number] =>
[bus_image] =>
[bus_stop_start] =>
[bus_stop_end] =>
)
[3] => Array
(
[id] => 1
[bus_id] => 1
[stop_order_id] => 14
[bus_time] => 11:58:00
[bus_direction] => 2
[trip] => 1
[created_at] => -0001-11-30 00:00:00
[updated_at] => -0001-11-30 00:00:00
[route_id] => 1
[stop_id] => 8
[stop_orders] => 14
[route_name] => Sydney
[seo_url] => sydney
[stop_name] => stop_8
[bus_name] => M.S
[bus_number] =>
[bus_image] =>
[bus_stop_start] =>
[bus_stop_end] =>
)
[4] => Array
(
[id] => 2
[bus_id] => 2
[stop_order_id] => 14
[bus_time] => 10:05:00
[bus_direction] => 1
[trip] => 1
[created_at] => -0001-11-30 00:00:00
[updated_at] => -0001-11-30 00:00:00
[route_id] => 1
[stop_id] => 8
[stop_orders] => 14
[route_name] => Sydney
[seo_url] => sydney
[stop_name] => stop_8
[bus_name] => J.S
[bus_number] =>
[bus_image] =>
[bus_stop_start] =>
[bus_stop_end] =>
)
[5] => Array
(
[id] => 2
[bus_id] => 2
[stop_order_id] => 22
[bus_time] => 10:55:00
[bus_direction] => 1
[trip] => 1
[created_at] => -0001-11-30 00:00:00
[updated_at] => -0001-11-30 00:00:00
[route_id] => 1
[stop_id] => 18
[stop_orders] => 22
[route_name] => Sydney
[seo_url] => sydney
[stop_name] => stop_18
[bus_name] => J.S
[bus_number] =>
[bus_image] =>
[bus_stop_start] =>
[bus_stop_end] =>
)
[6] => Array
(
[id] => 2
[bus_id] => 2
[stop_order_id] => 22
[bus_time] => 10:58:00
[bus_direction] => 2
[trip] => 1
[created_at] => -0001-11-30 00:00:00
[updated_at] => -0001-11-30 00:00:00
[route_id] => 1
[stop_id] => 18
[stop_orders] => 22
[route_name] => Sydney
[seo_url] => sydney
[stop_name] => stop_18
[bus_name] => J.S
[bus_number] =>
[bus_image] =>
[bus_stop_start] =>
[bus_stop_end] =>
)
[7] => Array
(
[id] => 5
[bus_id] => 5
[stop_order_id] => 27
[bus_time] => 11:07:00
[bus_direction] => 1
[trip] => 1
[created_at] => -0001-11-30 00:00:00
[updated_at] => -0001-11-30 00:00:00
[route_id] => 2
[stop_id] => 8
[stop_orders] => 5
[route_name] => Melbone
[seo_url] => Melbone
[stop_name] => stop_8
[bus_name] => R.S
[bus_number] =>
[bus_image] =>
[bus_stop_start] =>
[bus_stop_end] =>
)
[8] => Array
(
[id] => 5
[bus_id] => 5
[stop_order_id] => 32
[bus_time] => 12:50:00
[bus_direction] => 1
[trip] => 1
[created_at] => -0001-11-30 00:00:00
[updated_at] => -0001-11-30 00:00:00
[route_id] => 2
[stop_id] => 18
[stop_orders] => 10
[route_name] => Melbone
[seo_url] => Melbone
[stop_name] => stop_18
[bus_name] => R.S
[bus_number] =>
[bus_image] =>
[bus_stop_start] =>
[bus_stop_end] =>
)
)
所以在这个数组中我试图基于几个条件满足来对数组进行分组
1）获取buses stop_name=Stop_k和stop_name=Stop_s以及trip和bus_direction必须在stop_name=Stop_k和stop_name=Stop_s
我已经厌倦了制造新阵列，但看起来对我来说变得很复杂
$busGroup=[];
foreach ($response as $key=>$value){
if(!in_array($value->bus_name,$busGroup)){
$busGroup[$value->bus_name][$value->trip][$value->bus_direction][]=$value->toArray();
}
}
任何人都可以帮助我让它发挥作用。谢谢。 因为我试图使用查询获得结果但未能成功。我已经有一个问题 MYSQL AND query to satisfy on same column
即使我在查询中得到相同的结果，我也没关系
更新
我在laravel中的查询
$response=BusTimingModel::join('stop_orders','stop_orders.id','=','bus_timings.stop_order_id')
->join('routes','stop_orders.route_id','=','routes.id')
->join('stops','stop_orders.stop_id','=','stops.id')
->join('buses','buses.id','=','bus_timings.bus_id')
->whereIn('stops.stop_name',['stop_8', 'Stop_18'])
->get();
我也试过了以下查询
$response=BusTimingModel::join('stop_orders','bus_timings.stop_order_id','=','stop_orders.id')
->join('routes','stop_orders.route_id','=','routes.id')
->join('stops','stop_orders.stop_id','=','stops.id')
->join('buses','buses.id','=','bus_timings.bus_id')
->whereIn('stops.stop_name',['stop_8', 'stop_18'])
->havingRaw('bus_timings.bus_time BETWEEN CAST("01:59:00" AS time) AND CAST("12:00:00" AS time)')
->get();
预期结果 当用户在源到目的地之间搜索时，应用程序应返回源和目的地之间的所有公共汽车旅行（如果用户选择长时间，例如
如果我说的数组结果我需要根据几个条件按总线分组，例如同一个bus_name必须同时包含[stop_name] => Stop_8和[stop_name] => Stop_18和[trip]和[bus_direction]必须在[stop_name] => Stop_8和[stop_name] => Stop_18
此处更新了问题
此处附带的链接用于sql文件
答案 0 :(得分：1)
试试这个：
$response=BusTimingModel::
join('stop_orders','stop_orders.id','=','bus_timings.stop_order_id')
->join('routes','stop_orders.route_id','=','routes.id')
->join('stops','stop_orders.stop_id','=','stops.id')
->join('buses','buses.id','=','bus_timings.bus_id')
->where([['trip','=','bus_direction'],['stops.stop_name','=',$Stop_k]])
->orWhere([['trip','=','bus_direction'],['stops.stop_name','=',$Stop_s])
->get();
当然它可能会更好但是现在虽然我没有足够的信息但它还不错！