为什么我的应用程序没有传递给下一个活动

时间:2018-01-12 11:57:21

标签: java android loops

我试图从主要活动转到第二个活动并传递一个数字而且它不起作用 谁能证明我的错误是什么

P.S 任何人都可以告诉我如何做一个循环停止让用户按下按钮在EditText中添加文本,然后重置EditText并再次等待他插入另一个文本,直到数组填满

谢谢!!

public class MainActivity extends AppCompatActivity {

public static int numOfSails;
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

try{
    Button nextButton = (Button) findViewById(R.id.next_button);
    EditText sailsNumET = (EditText) findViewById(R.id.sails_num);
    numOfSails = Integer.parseInt(sailsNumET.toString());
    nextButton.setOnClickListener(new View.OnClickListener(){
        @Override
        public void onClick(View view){
            Intent addingIntent = new Intent(MainActivity.this,AddingActivity.class);
            addingIntent.putExtra("nos",numOfSails);
            startActivity(addingIntent);

        }
    });


     }catch(NumberFormatException e){

  }
 }
}

并且在第二个活动中这是代码

public class AddingActivity extends AppCompatActivity {
public ArrayList<Sail> sails = new ArrayList<Sail>();
public static int numOfSails;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.adding_main);
    final Button addButton = (Button) findViewById(R.id.add_button);
    final EditText minusInGallonsET = (EditText) findViewById(R.id.gallons_num);
    final TextView counterET = (TextView) findViewById(R.id.counter_id);
    Bundle bundle = getIntent().getExtras();
    this.numOfSails = bundle.getInt("nos",0);
    for (int i = 0 ; i< numOfSails; i++){
        sails.add(new Sail());
    }

    addButton.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            int counter = 0;
            for (Sail s : sails){
                s.setFuelInGallons(Integer.parseInt(minusInGallonsET.toString()));
                s.setSailNum(counter);
                counter++;
                counterET.setText(counter);
            }
               }
    });

 }
}

3 个答案:

答案 0 :(得分:0)

请检查此代码 在Xml文件

<EditText
    android:id="@+id/sails_num"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:inputType="number"/>

在活动文件

Button nextButton = (Button) findViewById(R.id.next_button);
        final EditText sailsNumET = (EditText) findViewById(R.id.sails_num);

        nextButton.setOnClickListener(new View.OnClickListener(){
            @Override
            public void onClick(View view){
                final int numOfSails = Integer.parseInt(sailsNumET.getText().toString().equals("")?"0":sailsNumET.getText().toString());
                Intent addingIntent = new Intent(Main11Activity.this,AddingActivity.class);
                addingIntent.putExtra("nos",numOfSails);
                startActivity(addingIntent);

            }
        });

答案 1 :(得分:0)

类似的东西:

public class SecondActivity extends AppCompatActivity {

    public void backToMain (View view) {
        Intent intent = new Intent(getApplicationContext(),MainActivity.class);
       intent.putExtra("ID", your_string);  //Heres what you want to pass. "ID" is needed to catch that given Intent on second activity
       startActivity(intent);
    }

}

还将onClickListener设置为按钮。 :)

答案 2 :(得分:0)

您正在存储由object.toString()方法返回的字符串。哪个不会返回用户插入的值。

numOfSails = Integer.parseInt(sailsNumET.toString());

要获取用户插入的值,请使用以下代码。

numOfSails = Integer.parseInt(sailsNumET.getText().toString());

请注意,editText.getText()返回一个Editable对象而不是字符串值,因此您必须使用toString()方法。