Question

好吧，我正在尝试使用下面附带的代码来获取菜单项和子菜单的描述，但我无法得到它。

我正在尝试获取“关于我们”的描述以及“我们的董事会成员”的描述：

对于菜单项（关于我们）工作正常，但由于某种原因，子菜单（我们的董事会和员工）不包含信息Set conn1 = CreateObject("ADODB.Connection") conn1.Open strcon1 strquery3 = "SELECT COLUMN1, COLUMN2 FROM TABLE_NAME" Set rs3 = CreateObject("ADODB.Recordset") Set rs3 = conn1.Execute(strquery3)，它只有description，{{ 1}}和ID，我已经尝试了URL子菜单对象（正如您在下面的代码中看到的那样），但它没有。

Title

任何人都知道为什么没有描述项目，如何激活它或可能的解决方案？提前谢谢。

Answer 1

自WordPress 3.0以来，您不再需要自定义助行器了！

有walker_nav_menu_start_el过滤器，请参阅https://developer.wordpress.org/reference/hooks/walker_nav_menu_start_el/

实施例

 function add_menu_description($item_output, $item, $depth, $args) {
        if (strlen($item->description) > 0 ) {
            // append description after link
            $item_output .= sprintf('<span class="description">%s</span>', esc_html($item->description));

            // insert description as last item *in* link ($input_output ends with "</a>{$args->after}")
            //$item_output = substr($item_output, 0, -strlen("</a>{$args->after}")) . sprintf('<span class="description">%s</span >', esc_html($item->description)) . "</a>{$args->after}";
        }

        return $item_output;
    }
    add_filter('walker_nav_menu_start_el', 'add_menu_description', 10, 4);

Answer 2

我几天前找到了一个解决方案，所以可能对某人有帮助，我遇到的问题是调用菜单function wp_get_menu_array($current_menu) { $array_menu = wp_get_nav_menu_items($current_menu); $menu = array(); foreach ($array_menu as $m) { if (empty($m->menu_item_parent)) { $menu[$m->ID] = array(); $menu[$m->ID]['ID'] = $m->ID; $menu[$m->ID]['title'] = $m->title; $menu[$m->ID]['url'] = $m->url; $menu[$m->ID]['classes'] = $m->classes; $menu[$m->ID]['description'] = $m->description; $menu[$m->ID]['children'] = array(); } } $submenu = array(); foreach ($array_menu as $m) { if ($m->menu_item_parent) { $submenu[$m->ID] = array(); $submenu[$m->ID]['ID'] = $m->ID; $submenu[$m->ID]['title'] = $m->title; $submenu[$m->ID]['url'] = $m->url; $submenu[$m->ID]['description'] = $m->description; //Line added; $menu[$m->menu_item_parent]['children'][$m->ID] = $submenu[$m->ID]; } } return $menu; }的功能，我必须在子菜单中添加说明，只是：

library(tm)

txt <- c("Your work is going to fill a large part of your life, 
       and the only way to be truly satisfied is to do what you
        believe is great work. 
       And the only way to do great work is to love what you do. 
       If you haven't found it yet, keep looking. Don't settle. 
       As with all matters of the heart, you'll know when you find it. 
       - Steve Jobs")

term_stats(VCorpus(VectorSource(txt)))[1:5,]

term count support
.        5       1
to       5       1
is       4       1


#Split txt into 4 docs
txt_df <- data.frame( txt = c(
"Your work is going to fill a large part of your life, 
 and the only way to be truly satisfied is to do what you 
 believe is great work." , 
 "And the only way to do great work is to love what you do." , 
 "If you haven't found it yet, keep looking. Don't settle." , 
 "As with all matters of the heart, you'll know when you find it. - 
 Steve Jobs"))

term_stats(VCorpus(VectorSource(txt_df$txt)))[1:6,]

term count support
.        5       4
you      4       4
,        3       3
the      3       3
to       5       2
is       4       2

如何访问子菜单的描述？

2 个答案: