Question

我的另一个初学者问题。我提前道歉，但你能帮帮我吗？所以我想创建这个随机数生成器，它将生成数字1-100并要求用户输入。用户应该猜测，直到他最终获得正确的号码。最后，程序应该打印出你猜测的xx尝试＆＃34;。所以问题是，当我测试代码时，两次运行正确，其他2次错误（尝试次数错误）。现在我也觉得代码可以用更好的方式编写，但不确切知道如何。谢谢

import java.util.Scanner;
import java.util.Random;
public class JavaApplication2018 
{
    public static void main(String[] args) 
    {
        Scanner input = new Scanner(System.in);
        System.out.println("Enter a number, please");
        int attempt = input.nextInt();
        Random dice = new Random();
        int number;
        number = dice.nextInt(100) + 1;
        int counter = 0;
       while (number > attempt) 
       {
           System.out.println("I imagined a bigger number. Guess again!");
           attempt = input.nextInt();
           counter++;
       }

       while (number < attempt)
       {
           System.out.println("I imagined a smaller number. Guess again!");
           attempt = input.nextInt();
           counter++;
       }

       if (number == attempt)
       {

           counter++;
       }


       System.out.println("You guessed from " + counter +". attempt" );

    }  


}

Answer 1

用户猜测一次，如果它大于随机数，那么它将再次迭代，如果不是，它将在第二次迭代时，如果猜测再次大于该尝试，则不会好的，代码将以你想要的结果结束。

while (number > attempt || number<attempt) 
       {
        if(number>attempt){
           System.out.println("I imagined a bigger number. Guess again!");}             
        else
           System.out.println("I imagined a smaller number. Guess again!");

        attempt = input.nextInt();
        counter++;
       }
if (number == attempt)
   {

       counter++;
   }


   System.out.println("You guessed from " + counter +". attempt" );

}

这段代码应该更好

Answer 2

首先，您不需要两个while。你可以将它们放在一个while中，然后将if放在其中：

while(number ! attempt){
if(number > attempt)
...
else
...
}
System.out.println("good gusse" );

第二，我需要更多有关错误的详细信息才能帮助您解决问题

Answer 3

用户引入第一个输入，然后进入无限循环，在该循环中将要求用户输入数字，直到最终猜到该值。此代码仅检查用户引入的值2倍最大值。如果它有帮助，请选择答案：D

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    System.out.println("Enter a number, please");
    int attempt = input.nextInt();
    int number;
    number = new Random().nextInt(101);
    int counter = 1;

    while (true) {

        attempt = input.nextInt();
        counter++;


        if (number > attempt) {

            System.out.println("I imagined a bigger number. Guess again!");

        }else if (number < attempt) {

            System.out.println("I imagined a smaller number. Guess again!");

        }else {

            System.out.println("You guessed from " + counter + ". attempt");
            break;

        }


    }

}

具有用户输入代码的随机数生成器无法正常工作

3 个答案: