Question

我的sql表包含以下列id PK，ip，check_type check_status：

id      ip             check_type    check_status
1       10.10.10.10    check1        FAIL
2       10.10.10.10    check2        PASS
3       10.10.10.11    check1        PASS
4       10.10.10.11    check2        PASS

我只想要表中有ips的{{1}}。因此，从上面的例子我的输出应该是Failed Check1 and Passed Check2

10.10.10.10

我收到错误

列ip不明确

Answer 1

SELECT DISTINCT
  (a.ip)
FROM table1 a
INNER JOIN table1 b
  ON a.ip = b.ip
WHERE a.check_status = 'FAIL'
AND a.check_type = 'check1'
AND b.check_status = 'PASS'
AND b.check_type = 'check2';

这将有效

你正在选择a和b中的ip，所以它给出错误，所以当你写a.ip或b.ip时它会正常工作

Answer 2

使用条件聚合：

SELECT ip
FROM table1
GROUP BY ip
HAVING SUM(CASE WHEN check_type = 'check1' AND check_status = 'FAIL'
                THEN 1 ELSE 0 END) > 0 AND
       SUM(CASE WHEN check_type = 'check2' AND check_status = 'PASS'
                THEN 1 ELSE 0 END) > 0

另一种更优雅的方式应该适用于MySQL：

SELECT ip
FROM table1
WHERE (check_type, check_status) IN (('check1', 'FAIL'), ('check2', 'PASS'))
GROUP BY ip
HAVING COUNT(DISTINCT check_type, check_status) = 2;

这是第二个查询的Demo，由@MKhalid提供

MYSQL查找状态失败的服务器

2 个答案: