Question

JavaFX很新，我在运行后显示图像时遇到了一些麻烦。这是给我带来麻烦的方法。

  private void lookUp(Site site) {

    String link = site.getLink();

    String imageName = link.replace("/", "1");
    imageName = imageName.replace(".", "4");
    imageName = imageName.replace(":", "3");


    if(site.getImagePath() != null){
        //what to do if this shit does have an image already
        System.out.println("sample/Resources/images/" + site.getImagePath() + ".jpg");
        String imagePath = "/sample/Resources/images/" + site.getImagePath() + ".jpg";
        imagePath.trim();



        System.out.println(site.getImagePath());
        System.out.println(System.getProperty("user.dir"));
        Image image = new Image(imagePath);

        webShot.setImage(image);

    }

    else{
        //What to do if the image doesn't exist
         Snapshot service = new Snapshot();
         service.setLink(site.getLink());

         service.setOnSucceeded(t -> {
             System.out.println("done:" + t.getSource().getValue());
             site.setImagePath(t.getSource().getValue().toString());
             progressToScreenShot.setProgress(100);
             progressToScreenShot.setOpacity(0);

             Image image = new Image("src/sample/Resources/images/" + site.getImagePath() + ".jpg");
             webShot.setImage(image);

         });

         service.setOnRunning(t -> {
             progressToScreenShot.setOpacity(1.0);
             progressToScreenShot.setProgress(service.getProgress());
         });

         service.start();



    }//End of Else

}

奇怪的是第二次运行，图像保存到文件夹，它将出现在菜单中。该服务使用名为grabItz的API返回网站的快照。给出的错误是网址Caused by: java.lang.IllegalArgumentException: Invalid URL or resource not found

但是，如果它是一个无效的URL或资源不存在，它是如何在第二次运行时出现的？

如何使用JavaFX

0 个答案: