我尝试创建一个接收用户提交的图像的页面,并自动将它们重定向到呈现图像的新页面。我的大部分代码都是从这里借来的:How to pass uploaded image to template.html in Flask。但我似乎无法让它发挥作用;我遇到了400:Bad Request。在我看来,图像不是在/static/images
下保存,但我不确定为什么。
以下是index.html
中的提交表单:
<form method="POST" action="{{ url_for('predict') }}" enctype="multipart/form-data">
<label for="file-input" class="custom-file-upload">
<i class="fa fa-cloud-upload"></i> Upload Image
</label>
<input name="image-input" id="file-input" type="file" align="center" onchange="this.form.submit();">
</form>
这是我的app.py
代码:
from flask import Flask, render_template, request, url_for, send_from_directory, redirect
from werkzeug import secure_filename
import os
UPLOAD_FOLDER = '/static/images/'
ALLOWED_EXTENSIONS = set(['png', 'jpg', 'jpeg', 'tiff'])
def allowed_file(filename):
return '.' in filename and \
filename.rsplit('.', 1)[1] in ALLOWED_EXTENSIONS
app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
@app.route('/')
def index():
return render_template("index.html")
@app.route('/predict/', methods=['POST', 'GET'])
def predict():
if request.method == 'POST':
file = request.files['file']
if file and allowed_file(file.filename):
filename = secure_filename(file.filename)
file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
return redirect(url_for('uploaded_file', filename=filename))
return '''
<!doctype html>
<title>Upload new File</title>
<h1>Upload new File</h1>
<form action="" method=post enctype=multipart/form-data>
<p><input type=file name=file>
<input type=submit value=Upload>
</form>
'''
@app.route('/show/<filename>')
def uploaded_file(filename):
return render_template('classify.html', filename=filename)
@app.route('/uploads/<filename>')
def send_file(filename):
return send_from_directory(UPLOAD_FOLDER, filename)
if __name__ == '__main__':
app.run(debug=True)
最后,我尝试使用以下代码在classify.html
中呈现它:
{% if filename %}
<h1>some text<img src="{{ url_for('send_file', filename=filename) }}"> more text!</h1>
{% else %}
<h1>no image for whatever reason</h1>
{% endif %}
我在哪里错了?
答案 0 :(得分:0)
我的输入中似乎错过了一个参数:name=file
中index.html
。添加修复错误。总而言之,输入行看起来像这样:
<input id="file-input" name=file type="file" align="center" onchange="this.form.submit();">