而不是输入
Clause
是否有任何... WHERE transaction HAS(1, 2, 3, 4, 5)
来检查一次这样的一个简单的设置?
var j = new Circle(100, 100, 200, 200, 20, 'red');
j.draw();
答案 0 :(得分:1)
使用group by
和having
:
SELECT name
FROM table
WHERE aid IN (1, 2, 3, 4, 5)
HAVING COUNT(DISTINCT aid) = 5;