你好我试着学习Stephen Grider的反应本地课程。我坚持从我的webservice加载数据并使用redux和lodash列出它们。我可以成功获取数据并可以在render(console.log)中看到它,但我的props在componentDidUpdate或componentWillMount中始终为null。 任何帮助表示赞赏,谢谢。 减速机是这样的;
import { TEST_FETCH, TEST_LOAD } from "../actions/types";
const INITIAL_STATE = { dataSource: [] };
export default (state = INITIAL_STATE, action) => {
switch (action.type) {
case TEST_FETCH:
return { ...state, loading: false, dataSource: action.payload.data };
case TEST_LOAD:
return { ...state, loading: true, error: "" };
default:
return state;
}
};
并且行动是;
import { TEST_LOAD, TEST_FETCH } from "./types";
export const getdata = ( ) => {
return dispatch => {
dispatch({ type: TEST_LOAD });
fetch("http://myserver/getdata", {
method: "GET",
headers: {
Accept: "application/json",
"Content-Type": "application/json"
}
})
.then(response => {
return response.json();
})
.then(responseData => {
return responseData;
})
.then(data => {
// return data;
dispatch({ type: TEST_FETCH, payload: data });
});
};
};
和页面是;
import _ from 'lodash';
import React, { Component } from "react";
import { View, Text, ListView } from "react-native";
import { connect } from "react-redux";
import { getdata } from "../actions";
class testList extends Component {
componentWillMount() {
this.props.getdata();
}
componentDidMount() {
console.log(this.props.myarray ); // myarray is empty
this.createDataSource(this.props.myarray);
}
componentDidUpdate() {
console.log(this.props.myarray ); // I tried this but still myarray is empty
this.createDataSource(this.props.myarray);
}
createDataSource({ dtsource }) {
// sure dtsource is null too
const ds = new ListView.DataSource({
rowHasChanged: (r1, r2) => r1 !== r2});
this.dataSource = ds.cloneWithRows(dtsource);
}
render() {
console.log(this.props.myarray); // if I write here,I can see my json's output
return <View>
<Text>Employee List</Text>
<ListView dataSource={this.props.myarray} renderRow={rowData => <Text
>
{rowData}
</Text>} />
</View>;
}
}
const mapStateToProps = state => {
const myarray= _.map(state.testForm.dataSource, function(v) {
return { ...v };
});
return { myarray};
};
export default connect(mapStateToProps , { getdata })(testList);
答案 0 :(得分:1)
我建议您使用FlatList,因为不推荐使用ListView并且性能不佳。在此期间,您可以使用下面的代码段将正确的对象传递给dataSource。您可能需要添加一些null
项检查,具体取决于您传递给myarray
的数据的状态。
import _ from 'lodash';
import React, { Component } from "react";
import { View, Text, ListView } from "react-native";
import { connect } from "react-redux";
import { getdata } from "../actions";
class testList extends Component {
constructor(props) {
super(props);
this.state = {
dataSource: new ListView.DataSource({
rowHasChanged: (r1, r2) => r1 !== r2}).cloneWithRows(props.myarray ? props.myarray : [])
};
}
componentDidMount() {
this.props.getdata();
}
componentDidUpdate() {
this.setState({
dataSource: this.state.dataSource.cloneWithRows(props.myarray ? props.myarray : [])
});
}
render() {
return <View>
<Text>Employee List</Text>
<ListView dataSource={this.props.myarray} renderRow={rowData => <Text
>
{rowData}
</Text>} />
</View>;
}
}
const mapStateToProps = state => {
const myarray = _.map(state.testForm.dataSource, function(v) {
return { ...v };
});
return { myarray};
};
export default connect(mapStateToProps , { getdata })(testList);