Question

我有以下查询，它为我提供了我想要的数据，但是，我需要CASE语句中的Cash，Credit和Check列的总和。我怎样才能做到这一点？如果可能，我想为此使用一个程序。

另外，对我来说，这个查询看起来并不高效。任何人都可以改进吗？在我看来，我应该能够设置变量，然后在我的CASE语句中使用它们，但不知道它是如何完成的。

SELECT
t1.order_id,
t3.price * SUM( t1.quantity ) AS subtotal,
( SUM( t1.discount ) + t3.discount ) / 100 AS disc,
t3.price * SUM( t1.quantity ) * ( t3.tax_state + t3.tax_fed ) /100 AS tax,
t3.price * SUM( t1.quantity ) - ( SUM( t1.discount ) + t3.discount ) / 100 + t3.price * SUM( t1.quantity ) * ( t3.tax_state + t3.tax_fed ) /100 AS total,
CASE t2.payment_type WHEN 'Cash'  THEN t3.price * SUM( t1.quantity ) - ( SUM( t1.discount ) + t3.discount ) / 100 + t3.price * SUM( t1.quantity ) * ( t3.tax_state + t3.tax_fed ) /100 ELSE 0.00 END AS cash,
CASE t2.payment_type WHEN 'Card'  THEN t3.price * SUM( t1.quantity ) - ( SUM( t1.discount ) + t3.discount ) / 100 + t3.price * SUM( t1.quantity ) * ( t3.tax_state + t3.tax_fed ) /100 ELSE 0.00 END AS card,
CASE t2.payment_type WHEN 'Check' THEN t3.price * SUM( t1.quantity ) - ( SUM( t1.discount ) + t3.discount ) / 100 + t3.price * SUM( t1.quantity ) * ( t3.tax_state + t3.tax_fed ) /100 ELSE 0.00 END AS check
FROM pos_item_order AS t1
Join pos_order AS t2 ON t2.order_id = t1.order_id
Join inv_item AS t3 ON t3.item_id = t1.item_id
GROUP BY t1.order_id, t1.item_id

编辑：当我说“我需要现金，信用和支票栏的总和”时，我的意思是每栏各自的总数。

Answer 1

这是一个令人毛骨悚然的查询，但对您已经拥有的内容进行简单的扩展会为您提供我认为您要求的内容：

SELECT t1.order_id,
       t3.price * SUM( t1.quantity ) AS subtotal,
       ( SUM( t1.discount ) + t3.discount ) / 100 AS disc,
       t3.price * SUM( t1.quantity ) * ( t3.tax_state + t3.tax_fed ) /100 AS tax,
       t3.price * SUM( t1.quantity ) - ( SUM( t1.discount ) + t3.discount ) / 100 + t3.price * SUM( t1.quantity ) * ( t3.tax_state + t3.tax_fed ) /100 AS total,
       CASE t2.payment_type WHEN 'Cash'
       THEN t3.price * SUM( t1.quantity ) - ( SUM( t1.discount ) + t3.discount ) / 100 + t3.price * SUM( t1.quantity ) * ( t3.tax_state + t3.tax_fed ) /100
       ELSE 0.00 END AS cash,
       CASE t2.payment_type WHEN 'Card'
       THEN t3.price * SUM( t1.quantity ) - ( SUM( t1.discount ) + t3.discount ) / 100 + t3.price * SUM( t1.quantity ) * ( t3.tax_state + t3.tax_fed ) /100
       ELSE 0.00 END AS card,
       CASE t2.payment_type WHEN 'Check'
       THEN t3.price * SUM( t1.quantity ) - ( SUM( t1.discount ) + t3.discount ) / 100 + t3.price * SUM( t1.quantity ) * ( t3.tax_state + t3.tax_fed ) /100
       ELSE 0.00 END AS check,
       CASE WHEN t2.payment_type IN ('Cash', 'Card', 'Check')
       THEN t3.price * SUM( t1.quantity ) - ( SUM( t1.discount ) + t3.discount ) / 100 + t3.price * SUM( t1.quantity ) * ( t3.tax_state + t3.tax_fed ) /100 ELSE 0.00 END AS cash_card_check
  FROM pos_item_order AS t1
  JOIN pos_order AS t2 ON t2.order_id = t1.order_id
  JOIN inv_item AS t3 ON t3.item_id = t1.item_id
 GROUP BY t1.order_id, t1.item_i

IN(...)符号可能不起作用;如果没有，你可以写出一个三向OR条件。但是，我不禁想到必须有一种更好的方法来构建查询。

此查询为您提供基本详细信息，包括付款类型。将其保存到临时表中，或者如果您的DBMS支持，则在WITH子句中使用命名的子表达式。

SELECT t1.order_id,
       t2.payment_type,
       t3.price * SUM( t1.quantity ) AS subtotal,
       ( SUM( t1.discount ) + t3.discount ) / 100 AS disc,
       t3.price * SUM( t1.quantity ) * ( t3.tax_state + t3.tax_fed ) /100 AS tax,
       t3.price * SUM( t1.quantity ) - ( SUM( t1.discount ) + t3.discount ) / 100 + t3.price * SUM( t1.quantity ) * ( t3.tax_state + t3.tax_fed ) /100 AS total,
       t3.price * SUM( t1.quantity ) - ( SUM( t1.discount ) + t3.discount ) / 100 + t3.price * SUM( t1.quantity ) * ( t3.tax_state + t3.tax_fed ) /100 AS payment
  FROM pos_item_order AS t1
  JOIN pos_order      AS t2 ON t2.order_id = t1.order_id
  JOIN inv_item       AS t3 ON t3.item_id = t1.item_id
 GROUP BY t1.order_id, t1.item_i, t2.payment_type

然后，您可以单独和联合汇总卡片，支票和现金。

Answer 2

很遗憾，您无法在其他表达式中使用派生列，但您可以use a subquery来实现您想要的目标。

从我的睡觉时间开始，如果其他人还没有打败我，我会明天试一试，但我想我会给你指明进入的时间。

如何获得列的总和

2 个答案: