Question

的结果

{#457 ▼
  +"id": 14
  +"amount": "110092"
  +"discount": 0
  +"images": "{"images":{"original":"\/uploads\/post_images\/2017\/1513070310.jpeg","300":"\/uploads\/post_images\/2017\/300_1513070310.jpeg","600":"\/uploads\/post_images\/2017\/600_1513070310.jpeg","900":"\/uploads\/post_images\/2017\/900_1513070310.jpeg"},"thumbnail":"\/uploads\/post_images\/2017\/300_1513070310.jpeg"} ◀"
  +"created_at": "2017-12-28 17:48:48"
  +"updated_at": "2017-12-28 19:24:18"
}

查询，我试图从thumbnail为images的图片列中获取JsonObject，但我收到此错误：

"Illegal string offset 'thumbnail'"

我的代码：

$userShoppings = \DB::table('payments as s')
    ->join('products as p', 's.product_id', '=', 'p.id')
    ->select('p.*', 's.*',\DB::raw('s.ordering_count * s.price as cost'))
    ->whereUserId(auth()->user()->id)
    ->first();

dd($userShoppings->images['thumbnail']);

或

dd($userShoppings->images['images']['thumbnail']);

错误：

"Illegal string offset 'images'"

我的模特：

class Shopping extends Model
{
    protected $fillable = [];

    protected $casts=[
        'images'=>'array'
    ];
}

class Payment extends Model
{
    protected $fillable = [];

    protected $casts=[
        'images'=>'array'
    ];
}

Answer 1

您需要将$userShoppings->images转换为json或数组才能使用它

Answer 2

它是一个JSON对象，请尝试：

 $userShoppings->images.thumbnail

laravel get获取jsonObject值

2 个答案: