取消引用指针

Question

我需要创建一个程序，它获取num1，num2及其地址的值以及pNum的值和pNum的derefrenced值。如何获得pNum的值和pNum的解除引用值？

这是到目前为止的代码。

#include <iostream>
using namespace std;

void inputDetails(int* n1, int* n2)
{
    if (n1 != nullptr && n2 != nullptr)
    {
        cout << "Enter two integers" << endl;
        cin >> *n1;
        cin >> *n2;
    }
}

void outputDetails(int num1, int num2)
{
    cout << "The value of your first number is " << num1 << endl;
    cout << "The value of your second number is " << num2 << endl;
    cout << "The address of your first number is " << &num1 << endl;
    cout << "The adress of your second number is " << &num2 << endl;
}

int main()
{
    int num1, num2;
    int temp1, temp2;
    int* pNum1 = &num1;
    int* pNum2 = &num2;

    inputDetails(pNum1, pNum2);
    outputDetails(num1, num2);

    cin.get();
    cin.clear();
    cin.ignore(numeric_limits<streamsize>::max(), '\n');
    return 0;
}